Question

How many grams of FeCl 3 are in 250. mL of a 0.100 M solution?

Answer 1

Answer:

The correct answer is option B

Explanation:

$Molarity=\frac{Weight}{Molecular \,weight} \frac{1000}{V(in \, ml)}$

Given values,

Molarity of $FeCl_3=0.100M$

Volume of solution, $V=250ml$

Molecular weight of $FeCl_3=162.2$

Substituting this values in Molarity formula, we get

$0.1=\frac{weight}{162.2} \times\frac{1000}{250} \\ \Rightarrow 16.22=weight\times4 \\ \Rightarrow weight=\frac{16.22}{4} \\ \therefore weight=4.06g$