You would look at the reactants and try to get the other side to have abou the same number of elements.
The formula for Keq for the first chemical reaction with
given Keq is:
<span>Keq 1 = [ HI ]^2 / [ H2 ] [ I2 ]</span>
<span>While the formula for Keq for the 2nd is:</span>
<span>Keq 2 = [ HI ] / [
H2 ]^(1/2) [ I2 ]^(1/2)</span>
We can see that the coefficients in the reaction are
equal to the exponents in the equilibrium equation. Therefore if we divide the
whole reaction by 2, then that means we have to take the square root of the
equilibrium equation. Or in this case,
Keq 2 = sqrt (Keq 1)
Keq 2 = sqrt (794)
<span>Keq 2
= 28.19</span>
The answer to this question is <span>OH- + HA ⇒ A- + H2O</span>. The conjugate acid in the buffer, HA, neutralizes added strong base, OH-.
Just need some point sorry
0.81 moles
Explanation:
cobalt chloride when dissolved in water dissociate into cobalt and chloride ions as shown;
CoCl₂ (s) → [Co²⁺](aq) + 2[Cl⁻] (aq)
The mole ratio between CoCl₂ and [Co²⁺] is 1 ; 1 while the mole ratio between CoCl₂ and [Cl⁻] is 1 : 2
Therefore; 0.27 moles of CoCl₂ will form;
(1 * 0.27) = 0.27 moles of [Co²⁺] ions
(2 * 0.27) = 0.54 moles of [Cl⁻] ions
Total moles of dissociated ions are;
0.27 + 0.54
= 0.81 moles