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yanalaym [24]
3 years ago
10

Wind direction is noted based on what direction the wind is coming FROM?

Physics
1 answer:
Katen [24]3 years ago
4 0

Answer:

yes, or it can be noted to where the wind if going to

Explanation:

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Both speed and velocity measure how fast something is moving. However, since speed is not a _________ it does not require a(n) _
Jet001 [13]

Both speed and velocity measure how fast something is moving. Hence, since speed is not a vector it does not require direction.

Speed only depends on the distance covered by the object and how much time it took to cover that distance. It does not care about the direction, it just depend on the length of the entire path covered. Whereas, velocity depends on magnitude as well as the direction of the object's motion for example: When an airplane is traveling, It is better to deal the motion with velocity and when we are moving in a car inside the city, we should deal the motion with speed.  

3 0
3 years ago
Mercury is added to a cylindrical container to a depth d and then the rest of the cylinder is filled with water. If the cylinder
jonny [76]

Answer:

0.10839 m

Explanation:

P_1 = Atmospheric pressure = 1 atm = 101325 Pa

P = Total pressure at bottom of mecury = 1.2 atm

g = Acceleration due to gravity = 9.81 m/s²

h = d = Depth of mercury

\rho_m = Density of mercury = 1.36\times 10^4\ kg/m^3

\rho_w = Density of water = 1000\ kg/m^3

Pressure at the bottom is of the cylinder is given by

P_2=P_1+\rho_wgh\\\Rightarrow P_2=101325+1000\times 9.81(0.7-d)

Pressure at the bottom of mercury is

P=P_2+\rho_mgh\\\Rightarrow 1.2\times 101325=101325+1000\times 9.81(0.7-d)+1.36\times 10^4\times 9.81\times d\\\Rightarrow 1.2\times 101325=123606d+108192\\\Rightarrow d=\dfrac{1.2\times 101325-108192}{123606}\\\Rightarrow d=0.10839\ m

The depth of the mercury is 0.10839 m

7 0
3 years ago
A student puts a beaker of boiling water where it touches a block of ice. Which two statements are true? A. Thermal energy will
rodikova [14]

Answer: C and D

Explanation: I’m pretty sure it’s C and D I got the same question but cold water let me know please, thanks!

6 0
4 years ago
Read 2 more answers
A box of mass 20kg is pulled up an inclined plane by a force of 285N. Given that the value of the incline angle is 30 degrees an
docker41 [41]

Given :

Mass of box , m = 250 kg.

Force applied , F = 285 N.

The value of the incline angle is 30°.

the coefficient of dynamic friction is \mu=0.72 .

To Find :

The speed with which the box is moving with, assuming it takes 4 seconds to reach the top of the incline.

Solution :

Net force applied in box is :

F=285 - mgsin\ \theta - \mu mg cos \ \theta\\ \\F=285-mg( sin \ \theta - \mu cos\ \theta)\\\\F=285 - 20\times 10( \dfrac{1}{2}+0.72\times \dfrac{\sqrt{3}}{2})\\\\F=60.29\ N

Acceleration , a=\dfrac{F}{m}=\dfrac{60.29}{20}=3.01\ m/s^2.

By equation of motion :

v=u+at\\\\v=0+3.01\times 4\\\\v=12.04\ m/s

Therefore, the speed of box is 12.04 m/s.

Hence, this is the required solution.  

6 0
3 years ago
Help I’ll give ndburbrbruejdmd
Brilliant_brown [7]

Answer:

Explanation:

1.{1,3}2. adn as if bruh ma dude

6 0
3 years ago
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