1,119,000 basically 746 times 150 then multiply that answer by 10
Complete question:
while hunting in a cave a bat emits sounds wave of frequency 39 kilo hartz were moving towards a wall with a constant velocity of 8.32 meters per second take the speed of sound as 340 meters per second. calculate the frequency reflected off the wall to the bat?
Answer:
The frequency reflected by the stationary wall to the bat is 41 kHz
Explanation:
Given;
frequency emitted by the bat, = 39 kHz
velocity of the bat,
= 8.32 m/s
speed of sound in air, v = 340 m/s
The apparent frequency of sound striking the wall is calculated as;

The frequency reflected by the stationary wall to the bat is calculated as;


Answer:
(A) Speed will be 
(b) Change in kinetic energy =
Explanation:
We have given mass of proton 
Acceleration of the proton 
Initial velocity u =
m/sec
Distance traveled by proton s = 3.90 cm = 0.039 m
(a) From third equation of motion we know that



(b) Initial kinetic energy 
Final kinetic energy 
So change in kinetic energy 
I can not solve the problem if I do not have the mass.