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Vera_Pavlovna [14]
2 years ago
10

A small car of mass 1200 kg traveling east at 60m/s collides at an intersection with a truck of mass 3000 kg that is traveling d

ue north at 40 m/s. The two vehicles are locked together. What is the velocity of the combined wreckage
Physics
2 answers:
lakkis [162]2 years ago
5 0

Answer:

11.4m/s I think mb not 100% lol

Explanation:

P=mv

P1 = 1200×60 = 72000

P2 = 3000×40 = 120000

120000+(-72000) = 48000

v=P÷m

m=1200+3000 = 4200

48000÷4200 = 11.4m/s

erik [133]2 years ago
5 0

v2f= 2⋅m1 (m2+m1) v1i + (m2−m1)(m2+m1) v2i v 2

meaning that

2 x 1200 ( 3000 + 1200) 60 + (3000-1200)(3000+1200) 40f =

2400 (4200) 60 + (1800) (4200) 40f =

10080000 (60) +  75600000 (40)

604800000 + 3024000000

3628800000? this is what i got

f = 2 ⋅ m 1 ( m 2 + m 1 ) v 1 i + ( m 2 − m 1 ) ( m 2 + m 1 ) v 2 i

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One horsepower is a unit of power equal to 746 W. How much energy can a 150 horsepower engine transform in 10.0 seconds
11111nata11111 [884]
1,119,000 basically 746 times 150 then multiply that answer by 10
7 0
3 years ago
while hunting in a cave a bat emits sounds wave of frequency 39 kilo hartz were moving towards a wall with a constant velocity o
MariettaO [177]

Complete question:

while hunting in a cave a bat emits sounds wave of frequency 39 kilo hartz were moving towards a wall with a constant velocity of 8.32 meters per second take the speed of sound as 340 meters per second. calculate the frequency​ reflected off the wall to the bat?

Answer:

The frequency reflected by the stationary wall to the bat is 41 kHz

Explanation:

Given;

frequency emitted by the bat, = 39 kHz

velocity of the bat, v_b = 8.32 m/s

speed of sound in air, v = 340 m/s

The apparent frequency of sound striking the wall is calculated as;

f' = f(\frac{v}{v- v_b} )\\\\f' = 39,000(\frac{340}{340 -8.32} )\\\\f' = 39978.29 \ Hz

The frequency reflected by the stationary wall to the bat is calculated as;

f_s = f'(\frac{v + v_b}{v} )\\\\f_s = 39978.29(\frac{340 + 8.32}{340} )\\\\f_s = 40,956.56 \ Hz

f_s\approx 41 \ kHz

3 0
3 years ago
Explain how a bathroom scale is like a biofeedback machine.
amid [387]

Answer:

                 

Explanation:

4 0
3 years ago
A proton (mass m = 1.67 × 10-27 kg) is being accelerated along a straight line at 2.50 × 1012 m/s2 in a machine. If the proton h
Veronika [31]

Answer:

(A) Speed will be 44.18\times 10^4m/sec

(b) Change in kinetic energy = 1560\times 10^{-19}      

Explanation:

We have given mass of proton m=1.67\times 10^{-27}kg

Acceleration of the proton a=2.50\times 10^{12}m/sec^2

Initial velocity u = 1.60\times 10^4 m/sec

Distance traveled by proton s = 3.90 cm = 0.039 m

(a) From third equation of motion we know that

v^2=u^2+2as

v^2=(1.60\times 10^4)^2+2\times 2.5\times 10^{12}\times 0.039

v=44.18\times 10^4m/sec

(b) Initial kinetic energy KE_I=\frac{1}{2}mv^2=\frac{1}{2}\times 1.67\times 10^{-27}\times (1.6\times 10^4)^2

Final kinetic energy KE_F=\frac{1}{2}mv^2=\frac{1}{2}\times 1.67\times 10^{-27}\times (44.18\times 10^4)^2

So change in kinetic energy \Delta KE=KE_F-KE_I=\frac{1}{2}\times 1.6\times 10^{-27}\times 10^8\times (44.18^2-1.6^2)=1560\times 10^{-19}J

6 0
3 years ago
A vertical spring (ignore its mass), whose spring constant is 1070 N/m, is attached to a table and is compressed 0.100 m.
harina [27]

I can not solve the problem if I do not have the mass.

3 0
3 years ago
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