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Alinara [238K]
3 years ago
11

Predator-prey relationship examples in the marine

Chemistry
1 answer:
astraxan [27]3 years ago
6 0

Answer: Seastars prey on mussels and shellfish which would otherwise have no other natural predators. Herbivorous fish like the butterflyfish pictured to the left prey on marine algae. Without this crucial predator-prey balance, the algae would over-grow, which would then kill coral, as they compete for the same resources.

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Examine the image of a potassium atom. (Image is below)
Bess [88]

Answer:

The answer to your question is D.

Explanation:

Potassium has 4 energy levels in the first level (A) has only 2 electrons,

in the second energy (B) level has 8 electrons, in the third energy level (C) also has 8 electrons and  in the fourth energy level has only one electron.

Valence electrons are located in the outermost shell so Potassium has only one electron located in the shell D.

7 0
4 years ago
Calculate the molarity when 14.6 g Ethanol (C2H5OH) is dissolved in a 2.10 L solution
fiasKO [112]

Answer:

0.15 M

Explanation:

14.6/46.07g/mol = 0.316 mol Ethanol.

0.316/2.1= 0.15 M

5 0
3 years ago
Are phase changes physical or chemical changes? why?
Studentka2010 [4]
Physical! Because they do not modify the nature of the substance ( if you look at the chemical level) and it is reversible

Vapor is H20
Water is H20
Ice is H20

A chemical changes is not reversible
Burning wood for example! And the reactants interact together to form a new product.
6 0
3 years ago
Read 2 more answers
Consider the following equilibrium:H2CO3(aq) + H2O(l) H3O+(aq) + HCO3-1(aq).What is the correct equilibrium expression?
BaLLatris [955]

<span>1.    </span>The equilibrium expression shows the ratio between products and reactants. This expression is equal to the concentration of the products raised to its coefficient divided by the concentration of the reactants raised to its coefficient. The correct equilibrium expression for the given reaction is:<span>

<span>H2CO3(aq) + H2O(l) = H3O+(aq) + HCO3-1(aq)

Kc = [HCO3-1] [H3O+] / [H2O] [H2CO3]</span></span>

8 0
3 years ago
How much heat is required to raise the temperature of 250.0 g of mercury by 52 degrees * C with a specific heat of 4.18
Goryan [66]
Heat required = M * C * (delta T)
= (Mass)*(Specific heat)*(temperature change)
= 250 * 4.18* 52 = 54340Joules.

I solve when unit of specific heat is (J/gC) if have another unit please tell me
5 0
3 years ago
Read 2 more answers
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