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MaRussiya [10]
3 years ago
10

What kind of reaction is represented by the dancing figures?

Chemistry
1 answer:
Darina [25.2K]3 years ago
6 0
C - single replacement reaction
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An element is made up from ?
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Answer:

Atoms

Explanation:

Elements are the chemical combinations of two or more atoms of the same kind

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Can anyone help me with 6-10 ? <br> I’ll mark as a brainliest.
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Answer:

based on this ball and stick model how many oxygen atoms are there in a milecule of 2 propanol

Explanation:

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5. A compound with a formula of lead (Pb) and sulfur (S) was determined using the method in this experiment. A sample of Pb was
Airida [17]

Answer:

The mass of S that reacted is 0.642g

Explanation:

In this case we have

⇒ mass of crucible and cover, 25.429g

⇒ mass of crucible, cover, and Pb, 29.465g

⇒ mass of crucible, cover and commass of crucible and coverpound formed, 30.107g

The mass of Pb reacted = mass of crucible, cover, and Pb - mass of crucible and cover = 29.465 - 25.429 = 4.036g

The mass of compound formed = mass of crucible, cover and commass of crucible and coverpound formed  - mass of crucible and cover = 30.107 - 25.429g = 4.678g

The mass of S reacted = Mass of compound formed - mass of Pb reacted = 4.678 -4.036 = 0.642g

The mass of S that reacted is 0.642g

7 0
4 years ago
An object’s mass is determined to be 32.5 g. When the object is placed in a graduated cylinder containing 175 mL of water, the w
MakcuM [25]
<h3><u>Given :-</u></h3>
  • Mass of object = 32.5 g

<h3><u>To Find </u><u>:</u><u>-</u></h3>
  • Dentity of the material

<h3><u>Solution:- </u></h3>

When the object is placed in a graduated cylinder containing 175 ml of water, the water in the cylinder rises to a level of 187.5 ml , this implies that volume of content in the container has increased , the increased volume is volume of the object placed

So, Volume of object

= Increased Volume - Initial volume

= > 187.5 -175

= > 12.5 ml

Since 1 ml = 1 cm³ we can write

\quad12.5 ml = 12.5 cm³

Now,

\green{ \underline { \boxed{ \sf{Density=  \frac{Mass}{Volume}}}}}

Putting Values -

\begin{gathered}\\\implies\quad \sf Density =  \frac{32.5}{12.5}  \\\end{gathered}

\begin{gathered}\\\implies\quad \sf Density =  \frac{325}{125}  \\\end{gathered}

\begin{gathered}\\\implies\quad \sf Density = 2.6 g/cm^3 \\\end{gathered}

>> The density of the material is 2.6 g/cm³

6 0
2 years ago
A chemistry student needs 55.0g of carbon tetrachloride for an experiment. by consulting the crc handbook of chemistry and physi
Tanzania [10]

Answer:

34.6 cm³

Explanation:

Given data

  • Mass of carbon tetrachloride (m): 55.0 g
  • Density of carbon tetrachloride (ρ): 1.59 g/cm³
  • Volume of carbon tetrachloride (V): ?

We can determine the volume of carbon tetrachloride that the student should pour out using the following expression.

ρ = m / V

V = m / ρ

V = 55.0 g / (1.59 g/cm³)

V = 34.6 cm³

4 0
3 years ago
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