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-Dominant- [34]
3 years ago
5

When of alanine are dissolved in of a certain mystery liquid , the freezing point of the solution is less than the freezing poin

t of pure . Calculate the mass of sodium chloride that must be dissolved in the same mass of to produce the same depression in freezing point. The van't Hoff factor for sodium chloride in . Be sure your answer has a unit symbol, if necessary, and round your answer to significant digits.

Chemistry
1 answer:
vitfil [10]3 years ago
7 0

Answer:

16.5 g

Explanation:

The van't Hoff factor is a relation between the ideal value of a solution's colligative properties and the observed colligative properties.

Check the attached files for detailed solution

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Which of the following most likely happens when the number of particles of a gas decreases?
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Answer: C. The number of collisions of gas particles decreases

Explanation: As temperature decreases so does everything else same with increase.

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What is the molarity of a solution that contains 14 moles of solute and 2 liters of solution?
Nata [24]

Answer:

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Explanation:

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Sodium thiosulfate, Na 2S 2O 3, is used as a "fixer" in black and white photography. Identify the reducing agent in the reaction
Tatiana [17]

Answer: Reducing agent in the given reaction is S_{2}O^{2-}_{3}.

Explanation:

A reducing agent is defined as an element which tends to lose electrons to other element leading to an increase in its oxidation number.

In the given reaction, oxidation state of sulfur in S_{2}O^{2-}_{3} is +2 and I_{2}(aq) has 0 oxidation state.

In S_{4}O^{2-}_{6}(aq) oxidation state of S is 2.5 and in 2I^{-}(aq) oxidation state of I is -1.

Since, an increase in oxidation state of S is occurring from +2 to +2.5. Hence, it is acting as a reducing agent.

Thus, we can conclude that reducing agent in the given reaction is S_{2}O^{2-}_{3}.

8 0
3 years ago
The primary product of the combustion of sulfur is:
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SO2 hfjkglhgdhjrklgwe
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A 10.50 gram sample of a compound is decomposed to yield 3.40 g Na, 2.37 g S, and 4.73 g O. What is the mass percentage of each
9966 [12]

Answer:

Na = 32.4% , % S = 22.6% and %O = 45.0%

Explanation:

% Na = 3.4/10.5. × 100%

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% O= 4.73/10.5 × 100%

= 45.0%xplanation:

6 0
3 years ago
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