When of alanine are dissolved in of a certain mystery liquid , the freezing point of the solution is less than the freezing poin
t of pure . Calculate the mass of sodium chloride that must be dissolved in the same mass of to produce the same depression in freezing point. The van't Hoff factor for sodium chloride in . Be sure your answer has a unit symbol, if necessary, and round your answer to significant digits.
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The question is incomplete, here is the complete question:
Calculate the mole fraction of the ionic species KCl in the solution A solution was prepared by dissolving 43.0 g of KCl in 225 g of water.
<u>Answer:</u> The mole fraction of KCl in the solution is 0.044
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
.....(1)
- <u>For water:</u>
Given mass of water = 225 g
Molar mass of water = 18 g/mol
Putting values in equation 1, we get:
- <u>For KCl:</u>
Given mass of KCl = 43 g
Molar mass of KCl = 74.55 g/mol
Putting values in equation 1, we get:
Mole fraction of a substance is given by:
- <u>For KCl:</u>
Moles of KCl = 0.577 moles
Total moles = [0.577 + 12.5] = 13.077 moles
Putting values in above equation, we get:
Hence, the mole fraction of KCl in the solution is 0.044