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AfilCa [17]
3 years ago
10

A student collected a 47.5 mL sample of gas in the lab at 0.8 atm pressure and 29.00C. What volume would this gas sample occupy

at standard conditions?
Chemistry
1 answer:
Sav [38]3 years ago
8 0

Answer:

the volume would be 69.034mL

Explanation:

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RUDIKE [14]

Answer:

A.) the transfer of energy through a solid, such as the Earth’s crust

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5 0
2 years ago
Which of the following is the best reason to read directions carefully before beginning any type of lab?
salantis [7]

Answer:

B

Explanation:i think

4 0
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3 0
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Which lunar phase will occur about four days after a waxing crescent?
Mamont248 [21]

Answer:3.5 days is awfully precise and waxing gibbous is awfully vague.Let’s just make sure we understand our terminology. Waxing means getting fatter and gibbous means fat. A waxing gibbous moon lasts for approximately 7 days from the first quarter phase right up to the full moon phase.By 3.5 days I’m assuming you mean half a week and simplifying the lunar phases to 28 days exactly.So we have:Day 0 New moon.Day 7 First quarter.Day 14 Full moon.Day 21 Third quarter.Day 28 New Moon.Between day 0 - 7 we have the waxing crescent phase.Between day 7–14 we have the waxing gibbous phase.Between day 14–21 we have the waning gibbous phase.Between day 21–28 we have the waning crescent phase.So 3.5 days from day 7 would take us to day 10.5 which would still leave us in the waxing gibbous phase. 3.5 days after day 10.5 would take us to the full moon or over into the waning gibbous phase since the full moon lasts only an instant.

Explanation:

3 0
2 years ago
What is the ph of 0.00035 M KOH
pashok25 [27]

Answer:

13.5

Explanation:

Potassium hydroxide fully ionizes when dissolved in water according to the following equation:

K

O

H

→

K

+

+

O

H

−

Now, let's find the relationship between

K

O

H

and

O

H

−

1

  :  

1

ratio

⇒

[

K

O

H

]

=

[

O

H

−

]

=

6.7

×

10

−

3

M

In any aqueous solution,

[

H

3

O

+

]

and

[

O

H

−

]

must satisfy the following condition:

[

H

3

O

+

]

[

O

H

−

]

=

K

w

[

H

3

O

+

]

=

K

w

[

O

H

−

]

[

H

3

O

+

]

=

1.0

×

10

−

14

6.7

×

10

−

3

[

H

3

O

+

]

=

1.5

×

10

−

12

M

Now, after finding the concentration of the hydronium ion, the pH of the solution is determined:

p

H

=

−

log

[

H

3

O

+

]

p

H

=

−

log

[

1.5

×

10

−

12

]

p

H

=

11.83

Other Method

Find the pOH using the concentration of the hydroxide ion, then use the formula

p

H

+

P

O

H

=

14

to find the pH.

8 0
3 years ago
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