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AfilCa [17]
2 years ago
10

A student collected a 47.5 mL sample of gas in the lab at 0.8 atm pressure and 29.00C. What volume would this gas sample occupy

at standard conditions?
Chemistry
1 answer:
Sav [38]2 years ago
8 0

Answer:

the volume would be 69.034mL

Explanation:

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You need to produce a buffer solution that has a pH of 5.50. You already have a solution that contains 10 mmol (millimoles) of a
balandron [24]

Answer:

56.9 mmoles of acetate are required in this buffer

Explanation:

To solve this, we can think in the Henderson Hasselbach equation:

pH = pKa + log ([CH₃COO⁻] / [CH₃COOH])

To make the buffer we know:

CH₃COOH  +  H₂O  ⇄   CH₃COO⁻  +  H₃O⁺     Ka

We know that Ka from acetic acid is: 1.8×10⁻⁵

pKa = - log Ka

pKa = 4.74

We replace data:

5.5 = 4.74 + log ([acetate] / 10 mmol)

5.5 - 4.74 = log ([acetate] / 10 mmol)

0.755 = log ([acetate] / 10 mmol)

10⁰'⁷⁵⁵ = ([acetate] / 10 mmol)

5.69 = ([acetate] / 10 mmol)

5.69 . 10 = [acetate] → 56.9 mmoles

6 0
3 years ago
How many significant figures are in 3.02 x 108 ?<br> a<br> 2<br> b 4<br> C 5<br> d 3
bija089 [108]

Answer:

C

Explanation:

the answer has 5 Numbers

7 0
3 years ago
1) Look at the graph. What is the independent variable and the dependent variable?
Xelga [282]

Answer:

Independent Variable = Years

Dependent Variable = Number of Mobiles phone owners

Explanation:

Independent variables are plotted on x-axis and the dependent variables are plotted on y-axis.

In given graph the "Years" belong to x-axis hence, years are the independent variables.

Also, "Number of Mobile phones owners" belong to y-axis hence, this number is the dependent variable.

5 0
2 years ago
I'm afraid I won't pass. And very nervous. Can you help me please.
daser333 [38]
Just look at the number in front also called coefficient (you have to balance the equations first, but all the questions here are balanced, so no worries). for q1.
in the balanced equation, the number in front of aluminum oxide is 2 (2 - this number Al2O3) and for aluminium is 4 as in (4 Al). so the ratio is 2:4. simplified it is 1:2. or write it out fully
2 Al2O3: 4 Al
ignore everything after the number.
2:4
same as 1:2
Aluminium oxide to oxygen
2 Al2O3: 3 O2
2:3
aluminum to oxygen
4 Al: 3 O2
4:3

question 2
Mercury oxide to Mercury
2 HgO : 2 Hg
2:2
same as 1:1
Mercury oxide to oxygen
2 HgO : O2
since oxygen in this case does not have a number written in front of it, the default is 1.
2: 1.
you should be able to do the rest
4 0
3 years ago
The source of bitterness in dark chocolate is the compound theobromine, an alkaloid present in cocoa beans. In a sample of dark
spin [16.1K]

Answer: 193 mg of theobromine are present in the sample.

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number of particles.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given molecules}}{\text {Avogadros number}}=\frac{6.45\times 10^{20}}{6.023\times 10^{23}}=1.07\times 10^{-3}moles

1 mole of theobromine (C_7H_8N_4O_2) weigh = 180 g

1.07\times 10^{-3}moles  of theobromine (C_7H_8N_4O_2) weigh = \frac{180}{1}\times 1.07\times 10^{-3}=0.193g=193mg   (1g=1000mg)

193 mg of theobromine are present in the sample.

5 0
3 years ago
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