<span>let x=gallons of current mixture to be drained
and replaced with pure antifreeze.
4-x=gallons of current mixture remaining in the car.</span>
<span>
0.15(4-x)+1.00x=0.50 x 4
0.6-.15x+x=2
0.85x=1.4
x=1.4/0.85 =1.65 gal
Thus, 1.65 gallons of current mixture to be drained and replaced with pure
antifreeze.</span>
Answer:
as the greatest heat capacity? a. 1,000 g of water b. 1,000 g of steel c. 1 g of water d. 1 g ... +1. kvargli6h and 1 other learned from this answer. Answer: a. 1,000 g of water ... Heat capacity of steel = 0.49 J/gram^0C. Hence 1,000 g of water will have greatest heat capacity.
Explanation:
Uh i did this because it made me curious... i may have done it wrong nothing happened
Balanced equation for the above reaction is as follows;
Mg(OH)₂ + 2HCl ---> MgCl₂ + 2H₂O
stoichiometry of Mg(OH)₂ to MgCl₂ is 1:1
mass of Mg(OH)₂ reacted - 1.82 g
number of moles of Mg(OH)₂ - 1.82 g/ 58.3 g/mol = 0.0312 mol
number of Mg(OH)₂ moles reacted - number of MgCl₂ moles formed
number of MgCl₂ moles formed - 0.0312 mol
mass of MgCl₂ formed - 0.0312 mol x 95.2 g/mol = 2.97 g
mass of MgCl₂ formed - 2.97 g
To get mL from mass just devide 1000g with 10.5 to get 95.23mL
