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3 years ago

13

The scientist at the weather office predicted the temperatures in the city route route for the next week I will be the weather t

onight change which of these could be the most likely reason scientist prediction was incorrect

1 answer:

Cloud [144]3 years ago

6 0

Answer:

lord

Explanation:

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Enter the formula for the compound cobalt(II) phosphate. Express your answer as a chemical formula.

alexira [117]

Answer:

$Co_3(PO_4)_2$

Explanation:

Naming of the ionic compounds:-

The name of the cation is written first and the the name of the anion is written after the name of the cation separated by single space.
The negative ion is written next and a suffix is added at the end of the negative ion. The suffix written is '-ide'.
In case of transition metals, the oxidation state are written in roman numerals in bracket in front of positive ions.

Hence, given ionic compound:-

Cobalt(II) phosphate

So, Cobalt will have a positive charge of +2

Phosphate is $PO_4^{3-}$

So, the formula is :-

Co $PO_4^{3-}$

2 3

$Co_3(PO_4)_2$

5 0

2 years ago

Why does a heating curve have horizontal plateaus at certain points during the heating process? What is happening at those point

DENIUS [597]

A <span>heating curve having horizontal plateaus at certain points during the heating process means that the process occurs at increase heating. </span>

4 0

3 years ago

If I add 5.0 mL of water to 8.0 mL of a 6.0M NaOH solution, what

erastova [34]

Answer:fdfgfdgfdgfdgfd

Explanation:

3 0

3 years ago

For the reaction x2 + y + z → xy + xz, it is found that doubling the concentration of x2 doubles the reaction rate, tripling the

andre [41]

R=[x2][y] rate law of the reaction
check:
if we double x2, r(new) =[2*x2][y]=2*[x2]*[y]=2*r
if we triple y, r(new) =[x2][3y]=3*[x2]*[y]=3*r
z- no effect, so z is not included

5 0

3 years ago

Read 2 more answers

16.25 g of water at 54 C relaeases 402.7 J. What will be its final temp?

leonid [27]

Data:
Q = 402.7 J → releases → Q = - 402.7 J
m = 16.25 g
T initial = 54 ºC
adopting: c = 4.184J/g/°C
ΔT (T final - T initial) = ?

Solving:

Q = m*c*ΔT
-402.7 = 16.25*4.184*ΔT
-402.7 = 67.99*ΔT
$\Delta\:T = \frac{-402.7}{67.99}$
$\boxed{\Delta\:T \approx -5.92\:^0C}$

If: ΔT (T final - T initial) = ?
$-5.92^0 = T_{final} - 54^0$
$T_{final} = 54^0 - 5.92^0$
$\boxed{\boxed{T_{final} = 48.08\:^0C}}\end{array}}\qquad\quad\checkmark$

8 0

3 years ago