<u>We are Given:</u>
Mass of the block (m) = 500 grams or 0.5 Kg
Initial velocity of the block (u) = 0 m/s
Distance travelled by the block (s) = 8 m
Time taken to cover 8 m (t)= 2 seconds
Acceleration of the block (a) = a m/s²
<u>Solving for the acceleration:</u>
From the seconds equation of motion:
s = ut + 1/2* (at²)
<em>replacing the variables</em>
8 = (0)(2) + 1/2(a)(2)²
8 = 2a
a = 4 m/s²
Therefore, the acceleration of the block is 4 m/s²
Answer:
Total impulse =
= Initial momentum of the car
Explanation:
Let the mass of the car be 'm' kg moving with a velocity 'v' m/s.
The final velocity of the car is 0 m/s as it is brought to rest.
Impulse is equal to the product of constant force applied to an object for a very small interval. Impulse is also calculated as the total change in the linear momentum of an object during the given time interval.
The magnitude of impulse is the absolute value of the change in momentum.

Momentum of an object is equal to the product of its mass and velocity.
So, the initial momentum of the car is given as:

The final momentum of the car is given as:

Therefore, the impulse is given as:

Hence, the magnitude of the impulse applied to the car to bring it to rest is equal to the initial momentum of the car.
What is your question exactly? I'm confused?
The wavelength of light is
given as 463 nm or can also be written as 463 x 10^-9 m. [wavelength = ʎ]
We know that the speed of
light is 299 792 458 m / s or approximately 3 x 10^8 m / s. [speed of
light = c]
Given the two values, we can calculate
for the frequence (f) using the formula:
f = c / ʎ
Substituting the given
values:
f = (3 x 10^8 m / s) / 463 x
10^-9 m
f = 6.48 x 10^14 / s = 6.48 x
10^14 s^-1
<span>f = 6.48 x 10^14 Hz</span>