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Naddik [55]
3 years ago
12

A baby elephant weighs 250 pounds on Earth. How much would the elephant weigh on Saturn?

Physics
1 answer:
BlackZzzverrR [31]3 years ago
8 0
Well since staurns gravity is 10.44 multiply the elephants weight times the gravity 
250x10.44 you will get 2610
hope i helped add me
Dosvedanya :)
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A person walks 45 m East and then walks 39 m at an angle 40◦ North of East. What is the magnitude of the total displacement? Ans
vredina [299]

Answer:

r = 78.95 m

Explanation:

given,

Person Walk in east, r₁ = 45 m

Then he walk, r₂= 39 m in the direction of 40◦ North of East.

writing the total displacement in x- direction

 r₁ₓ  = 45 m

 r₂ₓ = 39 cos 40°

  r₂ₓ = 29.87 m

total displacement in x-direction

rₓ = r₁ₓ + r₂ₓ

rₓ = 45 + 29.87

rₓ = 74.87 m

displacement in y-direction

r_{1y} = 0 m

r_{2y} = 39 sin 40°

r_{2y} = 25.07 m

total displacement in y- direction

  r_y = 25.07 m

using Pythagoras theorem for the magnitude calculation

 r = \sqrt{r_x^2 + r_y^2}

 r = \sqrt{74.87^2 +25.07^2}

        r = 78.95 m

The magnitude of total displacement is equal to 78.95 m.

8 0
3 years ago
A particle of mass 10 g and charge 80 mC moves through a uniform magnetic field,in a region where the free-fall acceleration is .
Alex777 [14]

Answer:

B=1.223\frac{T\cdot m}{s}\frac{1}{v}

Explanation:

According to the first Newton's law, when a particle moves with constant velocity, the sum of forces on it is zero. So, we have:

F_m=F_g

Here F_m=qvBsin\theta is the magnetic force and F_g=mg is the gravitational force. The velocity of the particle is perpendicular to the magnetic field, so \theta=90^\circ. Replacing and solving for B:

qvBsin(90^\circ)=mg\\B=\frac{mg}{qv}\\B=\frac{mg}{q}\frac{1}{v}\\B=\frac{(10*10^{-3}kg)(9.8\frac{m}{s^2})}{80*10^{-3}C}\frac{1}{v}\\B=1.223\frac{T\cdot m}{s}\frac{1}{v}

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4 years ago
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juin [17]

Answer:

Following are the solution to this question:

Explanation:

Law:

\to \theta= 180^{\circ}- 50^{\circ}- 25^{\circ}

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