Answer:
The car would travel after applying brakes is, d = 14.53 m
Explanation:
Given that,
The time taken to apply brakes fully is, t = 0.5 s
The velocity of the car, v = 29.06 m/s
The distance traveled by the car in 0.5 s, d = ?
The relation between the velocity, displacement, and time is given by the formula
d = v x t m
Substituting the values in the above equation,
d = 29.06 m/s x 0.5 s
= 14.53 m
Therefore, the car would travel after applying brakes is, d = 14.53 m
Answer:
The force that you must exert on the balloon is 1.96 N
Explanation:
Given;
height of water, h = 4.00 cm = 4 x 10⁻² m
effective area, A = 50.0 cm² = 50 x 10⁻⁴ m²
density of water, ρ = 1 x 10³ kg/m³
Gauge pressure of the balloon is calculated as;
P = ρgh
where;
ρ is density of water
g is acceleration due to gravity
h is height of water
P = 1 x 10³ x 9.8 x 4 x 10⁻²
P = 392 N/m²
The force exerted on the balloon is calculated as;
F = PA
where;
P is pressure of the balloon
A is the effective area
F = 392 x 50 x 10⁻⁴
F = 1.96 N
Therefore, the force that you must exert on the balloon is 1.96 N
Answer:
333 m
Explanation:
The following data were obtained from the question:
Initial velocity (u) = 0 m/s.
Time (t) = 8.14 s.
Final velocity (v) = 80.79 m/s.
Acceleration due to gravity (g) = 9.8 m/s²
Height (h) =?
v² = u² + 2gh
80.79² = 0 + (2 × 9.8 × h)
6527.0241 = 0 + 19.6h
6527.0241 = 19.6h
Divide both side by 19.6
h = 6527.0241 / 19.6
h = 333 m
Thus, the plane was at a height of 333 m when the package was dropped.
The big bang is a theory of our universe and many others along with making our solar system. Meanwhile, in other universes have are solar system as well that is why we see stars at night because the sun and it's rays are so bright during the day it blocks them out.
Given the mass of R-134a m = 300kg; Volume of the container V = 9 cu. meter; Temperature of R-134a T = 10 degrees Celsius;
Formula of specific volume : v = V / m = 9 / 300 = 0.03 cu. m / kg.
At T = 10 degrees Celsius from saturated R-134a tables, vf = 0.0007930 cu. m /kg; vg = 0.049403 cu. m/kg. We know v = vf + x (vg - vf), so 0.03 = 0.0007930 + x (0.049403 - 0.0007930), which makes x = 0.601.
Specific enthalpy of R-134a in the container is h = hf + x*hfg = 65.43 + (0.601 * 190.73). Answer is 180.0587 kJ/kg
