Answer:
0.5 rad / s
Explanation:
Moment of inertia of the disk I₁ = 1/2 MR²
M is mass of the disc and R is radius
Putting the values in the formula
Moment of inertia of the disc I₁ = 1/2 x 100 x 2 x 2
= 200 kgm²
Moment of inertia of man about the axis of rotation of disc
mass x( distance from axis )²
I₂ = 40 x 1.25²
= 62.5 kgm²
Let ω₁ and ω₂ be the angular speed of disc and man about the axis
ω₂ = tangential speed / radius of circular path
= 2 /1.25 rad / s
= 1.6 rad /s
ω₁ = ?
Applying conservation of angular moment ( no external torque is acting on the disc )
I₁ω₁ = I₂ω₂
200 X ω₁ = 62.5 X 1.6
ω₁ = 0.5 rad / s
Answer:
A. 24 m, 14 m/s
B. 8.0 m
Explanation:
Given:
x₀ = 6.0 m
v₀ = 4.0 m/s
a = 5.0 m/s²
t = 2.0 s
A. Find: x and v
x = x₀ + v₀ t + ½ at²
x = (6.0 m) + (4.0 m/s) (2.0 s) + ½ (5.0 m/s²) (2.0 m/s)²
x = 24 m
v = at + v₀
v = (5.0 m/s²) (2.0 s) + (4.0 m/s)
v = 14 m/s
B. Find x when v = 6.0 m/s.
v² = v₀² + 2a (x − x₀)
(6.0 m/s)² = (4.0 m/s)² + 2 (5.0 m/s²) (x − 6.0 m)
x = 8.0 m
V = IR
Where v is voltage I is current and r is resistance
So
V = 9
R = 12
V/R = I
9/12 = I
I = 0.75 A
Yes. If an object would be vertical, it would most likely have potential energy due to gravity.