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STALIN [3.7K]
2 years ago
8

The elements fluorine (F), chlorine (Cl), and Iodine are all part of the same ____________________ on the periodic table.

Chemistry
1 answer:
IgorC [24]2 years ago
4 0

Answer:

Halogen Family of elements

Explanation:

Group Seventeen

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1) 8700cm = ______ km
mart [117]

1. 0.087

2. 0.534

3. 1210000

4. 540

5. 0.00234

8 0
3 years ago
Burning one gallon of gasoline releases 20 pounds of CO2 into the air. Harry’s compact car can travel 25 miles on one gallon of
son4ous [18]
There are several information's already given in the question. Based on those information's, the answer can be easily deduced.
Amount of gasoline required by Harry's car to travel 25 miles = 1 gallon
Then
amount of gasoline required
by Harry's car to travel 15000 miles = 15000/25
                                                         = 600 gallons
So 
Amount of CO2 released by burning 1 gallon of gasoline = 20 pounds
Then
Amount of CO2 released
by burning 600 gallon of gasoline = 600 * 20
                                                      = 12000 pounds
From the above deduction, it can be concluded that the amount of CO2 that will be added by Harry's car to the atmosphere is 12000 pounds.
5 0
3 years ago
List two of the kingdoms found in the Eukarya domain
IrinaK [193]
Animalia and Plantae

Hope that helps
6 0
3 years ago
Carbon 14 decays to Carbon 12 and has a half-life of 5730 years. If a fossil is analysed and it has 5 grams of Carbon 14 and 15
Katen [24]

Answer:

im sorry but this question doesnt make sense

Explanation:

7 0
2 years ago
How many milliliters of 0.0896M LiOH are required to titrate 25.0 mL of 0.0759M HBr to the equivalence point?
slavikrds [6]

Answer:

V_{LiOH}=21.8mL

Explanation:

Hello,

In this case, during titration at the equivalence point, we find that the moles of the base equals the moles of the acid:

n_{LiOH}=n_{HBr}

That it terms of molarities and volumes we have:

M_{LiOH}V_{LiOH}=M_{HBr}V_{HBr}

Next, solving for the volume of lithium hydroxide we obtain:

V_{LiOH}=\frac{M_{HBr}V_{HBr}}{M_{LiOH}} =\frac{0.0759M*25.0mL}{0.0896M} \\\\V_{LiOH}=21.8mL

Best regards.

8 0
3 years ago
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