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Alex787 [66]
3 years ago
5

Two tiny conducting spheres are identical and carry charges of -22.0 µC and +46.0 µC. They are separated by a distance of 2.47 c

m. (a) What is the magnitude of the force that each sphere experiences, and is the force attractive or repulsive?
Physics
1 answer:
jeka943 years ago
3 0

Explanation:

Given that,

Charge 1, q_1=-22\ \mu C

Charge 2, q_2=+46\ \mu C

Separation between spheres, d = 2.47 cm

We need to find the magnitude of the force that each sphere experiences. It is given by the formula as follows :

F=k\dfrac{q_1q_2}{d^2}\\\\F=9\times 10^9\times \dfrac{22\times 10^{-6}\times 46\times 10^{-6}}{(2.47\times 10^{-2})^2} \\\\F=14928.94\ N\\\\F=1.49\times 10^4\ N

As the two charges have opposite sign, the force between them is attractive.

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