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3 years ago

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Two tiny conducting spheres are identical and carry charges of -22.0 µC and +46.0 µC. They are separated by a distance of 2.47 c

m. (a) What is the magnitude of the force that each sphere experiences, and is the force attractive or repulsive?

1 answer:

jeka943 years ago

3 0

Explanation:

Given that,

Charge 1, $q_1=-22\ \mu C$

Charge 2, $q_2=+46\ \mu C$

Separation between spheres, d = 2.47 cm

We need to find the magnitude of the force that each sphere experiences. It is given by the formula as follows :

$F=k\dfrac{q_1q_2}{d^2}\\\\F=9\times 10^9\times \dfrac{22\times 10^{-6}\times 46\times 10^{-6}}{(2.47\times 10^{-2})^2} \\\\F=14928.94\ N\\\\F=1.49\times 10^4\ N$

As the two charges have opposite sign, the force between them is attractive.

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3 years ago

(a) According to Hooke's Law, the force required to hold any spring stretched x meters beyond its natural length is f(x)=kx. Sup

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a) The work, measured in joules, is a physical variable represented by the following integral:

$W = \int\limits^{x_{f}}_{x_{o}} {F(x)} \, dx$

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$x_{o}$ , $x_{f}$ - Initial and final position, respectively, measured in meters.

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$A = \int\limits^{2\pi}_0 {[r(\theta)]^{2}} \, d\theta$

$A = 4\int\limits^{2\pi}_{0} {\sin^{2}5\theta} \, d\theta$

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