For Newton's second law, the force is equal to the product between the mass and the acceleration of the rocket:
From which we can rewrite the acceleration as
where m=7.0 kg.
The velocity of the rocket is the derivative of the acceleration:
and if we substitute x=9.0 m, we find the rocket velocity after 9.0 m:
Answer:
At the top of the hill.
Explanation:
As the roller coaster goes up the hill, kinetic energy (K.E) decreases, gravitational potential energy (G.P.E) increases .
As it reach the top of the hill, K.E becomes zero and G.P.E reaches <em>m</em><em>a</em><em>x</em><em>i</em><em>m</em><em>u</em><em>m</em> .
As it goes down the hill, K.E starts to increase and G.P.E decrease .
At the bottom of the hill, K.E reaches <em>maximum</em> and G.P.E becomes zero .
(Correct me it I am wrong)
Answer:
Explanation:
Given
See attachment
Required
Determine PCD and CPD
First, we need to calculate CPD
Since DPA is a straight line and CPA = 100;
We have that:
--- angle on a straight theorem
Substitute 100 for CPA
Subtract 100 from both sides
Next, we calculate PCD
We have that:
--alternate angle
In triangle PCD
--- angles in a triangle
Where
So, we have:
Subtract 136 from both sides
Answer:
V = 9.682 × 10^(-6) V
Explanation:
Given data
thick = 190 µm
wide = 4.20 mm
magnitude B = 0.78 T
current i = 32 A
to find out
Calculate V
solution
we know v formula that is
V = magnitude× current / (no of charge carriers ×thickness × e
here we know that number of charge carriers/unit volume for copper = 8.47 x 10^28 electrons/m³
so put all value we get
V = magnitude× current / (no of charge carriers ×thickness × e
V = 0.78 × 32 / (8.47 x 10^28 × 190 × 1.602 x 10^(-19)
V = 9.682 × 10^(-6) V
