Answer:
Goal address: Based on the above Ethernet outline design, we get that the goal address begins from the first hex worth and is of size 12 hex values (got from question 1). In light of the bundle given, we get that the goal address is 6c40 0889 c448.
Source address: Similarly, the source address begins after the goal address and is of size 12 hex values (got from question 1). Thus, the appropriate response is f832 e4a7 fb38.
Type/Length: The sort/length begins after the source address and is of size 4 hex values (got from question 1). Thus, the appropriate response is 0806.
Data (Payload): The data(payload) begins after the sort/length and finishes not long before FCS(Checksum) which is of 4 bytes for example 4 * 2 = 8 hex qualities. So the information comprises of everything between the 'type/length' and 'CRC'. We persuade the CRC to be c0a8 01f2. Henceforth, the appropriate response is 0001 0800 0604 0002 f832 e4a7 bf38 c0a8 0101 6c40 0889 c448.
Question 4:
The Ethernet parcel type characterizes the convention utilized for sending the bundle information. We realize that type 0x0800 demonstrates the IPv4 convention, 0x0806 shows an ARP convention, and 0x86DD demonstrates an IPv6 convention. In light of the appropriate response we got in Question 3, we realize that the sort/length esteem for the given parcel is 0806, which implies that convention utilized for sending the information bundle was ARP convention.
Tech A because it is best to use a knife
The three exposure techniques in photolithography are:
- Contact
- Proximity
- Projection
Alternatives to photolithography in IC processing include;
- X-ray
- UV
- Ion, and
- Electron lithography
<h3>
What is Photolithography?</h3>
Photolithography is a term in integrated circuit development that describes the patterned films that are formed when a beam of light falls on a substance.
This phenomenon protects the surface of sensitive materials such as glass during some operations like etching. UV and X-rays can be used for this purpose.
Learn more about photolithography here:
brainly.com/question/13650094
#SPJ11
Answer:
time need = 17.65 minutes
Explanation:
given data
water flows in = 22 liters/minute
water flows out = 5 liters/minute
volume of water needed for a bath = 0.30 m³ = 300 Liters
Density of water = 1000 kg/m³
solution
we get here time for need to fill bath that is express as
time need =
.........................1
put here value and we will get
time need =
time need = 17.65 minutes
Answer:
C which is square millimeters which is right.