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Snezhnost [94]
4 years ago
8

Why do we increase the surface area of a solid when dissolving?

Chemistry
2 answers:
love history [14]4 years ago
8 0
To increase the rate of dissolution 
astra-53 [7]4 years ago
3 0
Increasing the rate of it
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Serhud [2]

Answer:

D)3

Explanation:

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3 years ago
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Consider the following molecules with trigonal planar geometry. Carbonate (CO32−) and nitrate (NO3−) both exhibit resonance, whe
Arturiano [62]

Answer:

See explanation.

Explanation:

Carbonate and Nitrate: during double resonance the double bond revolves around each oxygen. This creates an atmosphere equal to each O-C-O link, then all 1200.

Phosgene: being that the atmosphere changes for each atom the bond angle should be 120, but a deviation occurs, since oxygen is more electronegative than Cl and O, so it is doubly linked. The Cl-C-O bond increases because the O and Cl repel each other, and a 124.3 bond angle is created between Cl-C-O, decreasing the Cl-C-Cl bond angle to 111.4 degrees.

See the result in the attached graph.

Hope this helps!

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3 years ago
If two electrons in the same atom have the same value of "l"
lesya692 [45]

Answer:

If two electrons in the same atom have the same value of "l", they are If two electrons in the same atom have the same value of "l", they are in the same orbital. in the same sublevel, but not necessarily in the same level. in different levels and in different shaped orbitals. in the same level, but different sublevel.

3 0
3 years ago
The equilibrium of 2H 2 O(g) 2H 2 (g) + O 2 (g) at 2,000 K has a Keq value of 5.31 x 10-10. What is the Keq expression for this
nevsk [136]

Answer:

5.31*10^{-10} = \frac{[]H_{2}]^{2}[O_{2}]}{[H_{2}O]^{2}}

Explanation:

For a chemical reaction, equilibrium is a state at which the rate of the forward reaction equals that of the reverse reaction. The equilibrium constant Keq is a parameter characteristic of this state which is expressed as a ratio of the concentration of the products to that of the reactants.

For a hypothetical reaction:

xA + yB ⇄ zC

The equilibrium constant is :

Keq = \frac{[A]^{x}[B]^{y}}{[C]^{z} }

The given reaction involves the decomposition of H2O into H2 and O2

2H_{2}O\rightleftharpoons 2H_{2} + O_{2}

The equilibrium constant is expressed as :

Keq = \frac{[]H_{2}]^{2}[O_{2}]}{[H_{2}O]^{2}}

Since Keq = 5.31*10^-10

5.31*10^{-10} = \frac{[]H_{2}]^{2}[O_{2}]}{[H_{2}O]^{2}}

3 0
3 years ago
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A mouse has 20 chromosomes. If one of its cells goes through mitosis, how many cells would be present after mitosis?
Anastasy [175]

Answer:

22

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when a cell goes through mitosis, it duplicates the amount of its subcellular structures, so it will create 2 more clones. So before it was 20, but one goes through mitosis and preduces two more daughter cells, meaning 22.

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3 years ago
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