All categories

4 years ago

Why do we increase the surface area of a solid when dissolving?

Chemistry

2 answers:

love history [14]4 years ago

8 0

To increase the rate of dissolution

astra-53 [7]4 years ago

3 0

Increasing the rate of it

You might be interested in

Solve this problem using the appropriate law.

Irina-Kira [14]

Answer:

6.17 L

Explanation:

7 0

3 years ago

Which is an overall second-order reaction?<br> R=k[A]2 [b]2<br> R=k[A][B]<br> R=k<br> R=k[B]

masha68 [24]

R=K[A]2 [b]2 HOPE THIS HELPS

4 0

3 years ago

What is the wavelength of spectral line resulted from the electron transition from n=3 to n=2 in a hydrogen atom.

MakcuM [25]

Answer:

$\lambda=6.56x10^{-7}m$

Explanation:

Hello there!

In this case, it possible to use the Rydberg equation in order to calculate the wavelength for this transition from n=3 to n=2 as shown below:

$\frac{1}{\lambda} =R_H(\frac{1}{n_f^2}-\frac{1}{n_i^2} )$

Thus, we plug in the corresponding energy levels and the Rydberg constant to obtain:

$\frac{1}{\lambda} =10973731.6m^{-1}(\frac{1}{2^2}-\frac{1}{3^2} )\\\\\frac{1}{\lambda} =1524129.4m^{-1}\\\\\lambda=\frac{1}{1524129.4m^{-1}} \\\\\lambda=6.56x10^{-7}m$

Best regards!

5 0

4 years ago

How many moles of N2O5 are needed to produce 7.90 g of NO2? 2N2O5 = 4NO2 + O2

miv72 [106K]

Moles of N2O5 = moles of NO2 * ( 2 moles of N2O5 / 4 moles of NO2

3 0

3 years ago

Read 2 more answers

3. Given 20g of Barium Hydroxide, how many grams of

anastassius [24]

The number of grams of ammonium nitrate (NH₄NO₃) it would take for all the barium hydroxide to react is 18.7g

First, we will write the balanced chemical equation for the reaction

The balanced chemical equation for the reaction is

Ba(OH)₂ + 2NH₄NO₃ → 2NH₄OH + Ba(NO₃)₂

This means, 1 mole of barium hydroxide is required to react with 2 moles of ammonium nitrate

Now, we will calculate the number of moles of barium hydroxide present.

Mass of barium hydroxide (Ba(OH)₂) = 20 g

Using the formula

$Number\ of\ moles = \frac{Mass}{Molar\ mass}$

Molar mass of Ba(OH)₂ = 171.34 g/mol

∴ Number of moles of Ba(OH)₂ present = $\frac{20}{171.34}$

Number of moles of Ba(OH)₂ present = 0.116727 mole

Now,

Since 1 mole of barium hydroxide is required to react with 2 moles of ammonium nitrate

Then,

0.116727 mole of barium hydroxide will react with 2 × 0.116727 mole of ammonium nitrate

2 × 0.116727 = 0.233454 mole

∴ Number of moles of NH₄NO₃ required is 0.233454 mole

Now, for the mass of ammonium nitrate (NH₄NO₃) required

From the formula

Mass = Number of moles × Molar mass

Molar mass of NH₄NO₃ = 80.043 g/mol

∴ Mass of NH₄NO₃ required = 0.233454 × 80.043

Mass of NH₄NO₃ required = 18.68636 g

Mass of NH₄NO₃ required ≅ 18.7g

Hence, the number of grams of ammonium nitrate (NH₄NO₃) it would take for all the barium hydroxide to react is 18.7g

Learn more on determining mass of reactant required here: brainly.com/question/11232389

6 0

2 years ago