1.386 g of Mg ribbon combusts to form 2.309 g of oxide product. The mass percent of oxygen in the oxide is 40.0 %.
Let's consider the reaction for the combustion of Mg.
Mg + 1/2 O₂ ⇒ MgO
1.386 g of Mg combusts to form 2.309 g of MgO. We want to determine the mass of oxygen in MgO. According to Lavoisier's law of conservation of mass, matter is not created nor destroyed over the course of a chemical reaction. Then, the mass of Mg in the reactants is equal to the mass of Mg in MgO. The mass of the magnesium oxide is the sum of the masses of magnesium and oxygen. The <u>mass of oxygen in the oxide</u> is:
We can calculate the mass percent of O in MgO using the following expression.
You can learn more about mass percent here: brainly.com/question/14990953
Answer:
I'm feeling nice today so heres the answer
Explanation:
In the portion of the cell membrane shown in the diagram, the arrow indicates the process of active transport.
Explanation:
Active transport is one of the mechanisms of transmembrane transport, which involves the use of energy. The diagram (see image) shows the hydrogen (H⁺) output from the cytoplasm to the extracellular space, through an H⁺ pump —consuming ATP— which represents an active transport process.
The hydrophobic nature of the cell membrane prevents the free passage of hydrosoluble elements or ions, as H⁺, so they require the use of active transport to pass through it.
The other options presented are not correct, because
Respiration is a process that occurs in the mitochondria.
Diffusion is a passive transport process that does not require energy.
Cellular recognition depends on membrane proteins that act as specific receptors.
Your answer would be a change in odor! Hope this helps! ;D
Answer:
The mole fraction of benzene and toluene in solution containing mole fraction of benzene and toluene in solution containing is 45.9%
Explanation:
don't worry
its is correct!
Answer:
-Cations: They are formed by an atom losing an electron or electrons.
-Anions: They are formed by an atom gaining an electron or electrons.
