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2 years ago

1. The hockey puck is given an initial speed of 20.0m/s on a frozen pond. The

Physics

2 answers:

DerKrebs [107]2 years ago

6 0

Answer:

B.o.19

Explanation:

andreyandreev [35.5K]2 years ago

5 0

Yurooo iwhvrn u w. N f c

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A particle with charge − 2.74 × 10 − 6 C −2.74×10−6 C is released at rest in a region of constant, uniform electric field. Assum

s2008m [1.1K]

Answer:

241.7 s

Explanation:

We are given that

Charge of particle= $q=-2.74\times 10^{-6} C$

Kinetic energy of particle= $K_E=6.65\times 10^{-10} J$

Initial time= $t_1=6.36 s$

Final potential difference= $V_2=0.351 V$

We have to find the time t after that the particle is released and traveled through a potential difference 0.351 V.

We know that

$qV=K.E$

Using the formula

$2.74\times 10^{-6}V_1=6.65\times 10^{-10} J$

$V_1=\frac{6.65\times 10^{-10}}{2.74\times 10^{-6}}=2.43\times 10^{-4} V$

Initial voltage= $V_1=2.43\times 10^{-4} V$

$\frac{\initial\;voltage}{final\;voltage}=(\frac{initial\;time}{final\;time})^2$

Using the formula

$\frac{V_1}{V_2}=(\frac{6.36}{t})^2$

$\frac{2.43\times 10^{-4}}{0.351}=\frac{(6.36)^2}{t^2}$

$t^2=\frac{(6.36)^2\times 0.351}{2.43\times 10^{-4}}$

$t=\sqrt{\frac{(6.36)^2\times 0.351}{2.43\times 10^{-4}}}$

$t=241.7 s$

Hence, after 241.7 s the particle is released has it traveled through a potential difference of 0.351 V.

6 0

3 years ago

You are on a cruise ship traveling north at a speed of 13 m/s with respect to land. 1) if you walk north toward the front of the

Brrunno [24]

In order to find the our own velocity with respect to land,we need to apply the theory of relative velocity.

Now consider the velocity of the ship traveling towards the north with respect to land as A.Consider our own velocity headed northwards as B.

The relative velocity is the velocity that the body A would appear to an observer on the body B and vice versa.

In this case the relative velocity would be arrived by summing up our velocity with the velocity of the ship as the object (I) is travelling in the ship.

Relative velocity = Velocity of Body A+ Velocity of Body B.

Velocity of the ship traveling towards the north with respect to land(A)= 13.0m/s. (Given)

Our own velocity headed northwards(B)= 2.8 m/s.

Relative velocity = Velocity of Body A+ Velocity of Body B.

Relative velocity= 13.0 + 2.8 = 15.8m/s.

Thus our own velocity with respect to the land is 15.8 m/s.

5 0

3 years ago

Which instrument is launched into the atmosphere to collect pressure, temperature, humidity, wind speed, and other data?

koban [17]

C. Radiosonde is the answer

the above mentioned is not correct

5 0

3 years ago

Radio wave radiation falls in the wavelength region of 10.0 to 1000 meters. What is the energy of radio wave radiation that has

dmitriy555 [2]

Answer:

Explanation:

Given

Wavelength of radiation $\lambda =784\ m$

We know Energy of wave with wavelength $\lambda$ is given by

$E=\frac{hc}{\lambda }$

where h=Planck's constant

c=velocity of light

$\lambda$ =wavelength of wave

$E=\frac{6.626\times 10^{-34}\times 3\times 10^8}{784}$

$E=2.53\times 10^{-28}\ J$

Hence the energy of the wave with wavelength 784 m is $2.53\times 10^{-28}\ J$

7 0

3 years ago

A rescue team is searching for Andrew, a geologist who was stranded while conducting research in the mountains of Colorado. The

Sindrei [870]

Answer:

I = 9.82 10⁻⁷ W / m²

Explanation:

The intensity of the sound wave is the energy of the wave between the order per unit area of the same

I = P / A = E / T A

the energy is calculated by integrating the mechanical energy in a period, where the mass is changed by the density and ‘s’ is the amplitude of the sound wave

I = ½ ρ v (w s)²

I = ½ 1.35 328 (2π 530 2.00 10⁻⁸)²

I = 221.4 (4.435 10⁻⁹)

I = 9.82 10⁻⁷ W / m²

4 0

3 years ago