Answer:
, assuming that the gravitational field strength is .
Explanation:
Notice that both the speed and the direction of motion of this block are constant. In other words, the velocity of this block is constant.
By Newton's Second Law, the net force on this block would be . External forces on this block should be balanced. Thus, the magnitude of the (downward) weight of this block should be equal to the magnitude of the (upward) force that the boy applies on this block.
Let denote the mass of this block. It is given that . The weight of this block would be:
.
Hence, the force that the boy applies on this block would be upward with a magnitude of .
The mechanical work that a force did is equal to the product of:
- the magnitude of the force, and
- the displacement of the object in the direction of the force.
The displacement of this block (upward by ) is in the same direction as the (upward) force that this boy had applied. Thus, the work that this boy had done would be the product of:
- the magnitude of the force that this boy exerted, , and
- the displacement of this block in the direction, .
.
There's not enough information to find an answer.
I think the idea here is that in descending (416 - 278) = 138 meters,
the glider gives up some gravitational potential energy, which
becomes kinetic energy at the lower altitude. This is all well and
good, but we can't calculate the difference in potential energy
without knowing the mass of the glider.
Answer:
a) Vb = 4.65m/s at 25.46° due south of east
b) t = 119s
c) d = 238m
d) 28.43° due north of east.
e) Vb = 3.69m/s due east
f) t = 135.5s
Explanation:
Velocity relative to the earth is:
Vb = 4.65m/s < -25.46°
Since the distance to travel is 500m:
The distance on the y-axis is given by:
If the final position is directly east from the starting position:
From the y-components:
Solving for β:
β=28.43°
With this angle, the velocity would be:
Vb = 4.2*cos(28.43°) = 3.69m/s
And the time it would take it to cross:
t = 500/3.69 = 135.5s
All periodic motions are not circular bcox they aren't similar to each other as u know the motion repeats the periodic table and also repeats itself of the tym perform the motion of the periodic...
Propose a unique explanation