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astra-53 [7]
4 years ago
13

Help me with this question please

Physics
1 answer:
svp [43]4 years ago
5 0
10 11 12 10 18
14 16 12 13 13
13 14 15 13 13
8 10 16 16 13
They're all in the same order as the paper
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A coin completes 18 spins in 12 seconds. The centripetal acceleration of the edge of the coin is 2.2 m/s2. The radius of the coi
stellarik [79]

Answer:

2.5 cm

Explanation:

Number of spins in 12 seconds = 18

Number of spins in 1 second = 18 / 12 = 1.5

Number of spins in one second is called frequency.

f = 1.5 rps

ac = 2.2 m/s^2

Let r be the radius of coin

Centripetal acceleration, ac = r x w^2

2.2 = r x ( 2 x 3.14 x 1.5) ^2

2.2 = r x 88.7364

r = 0.025 m = 2.5 cm

3 0
4 years ago
Read 2 more answers
A 0.100-kg stone rests on a frictionless, horizontal surface. A bullet of mass 6.00 g, travel- ing horizontally at 350 m>s, s
mariarad [96]

Answer:

Magnitude is 25.8 m/s and direction is 35.5^{o}

Explanation:

From the law of conservation of linear momentum

m_{b}v_{ib}+ m_{s}v_{is}= m_{b}v_{fb}+ m_{b}v_{fs} where m_{b} and m_{s} are masses of bullet and stones respectively, v_{ib} and v_{is} are the initial velocities of bullet and stone respectively, v_{fb} and v_{fs} are the final velocities of bullet and stone respectively

Substituting 6g=0.006 Kg for mass of bullet, 0.1Kg for mass of stone, 350 m/s for initial velocity of bullet and 250 m/s as final velocity for stone but initial velocity of stone is zero

0.006 Kg *350 m/s (\hat i)+0.1 Kg*0=0.006 Kg* 250 m/s (\hat j)+0.1*v_{fs}

2.1 Kg.m/s(\hat i)=1.5 Kg.m/s(\hat j)+ 0.1*v_{fs}

0.1*v_{fs}=2.1 Kg.m/s(\hat i)- 1.5 Kg.m/s(\hat j)

v_{fs}=21 Kg.m/s(\hat i)- 15 Kg.m/s(\hat j)

|v_{fs}|=\sqrt {(v_{x}^{2}+v_{y}^{2})}

Substituting 21 for v_{x} and 15 for v_{y}

|v_{fs}|=\sqrt {(21^{2}+15^{2})}=25.8 m/s

To find direction

tan\theta=\frac {v_{y}}{v_{x}}

\theta=tan^{-1}(\frac {15}{21})=35.5^{o}

Therefore, magnitude is 25.8 m/s and direction is 35.5^{o}

8 0
4 years ago
Please help !!!!!!!!,
garik1379 [7]

Answer:

I think that it's C

5 0
3 years ago
What is the speed of a walking person in m/s if the person travels 1000 m in 20 minutes?
Nata [24]

Answer:

0.83m/s

Explanation:

Given parameters:

distance  = 1000m

time taken  = 20min

Unknown:

Speed of the walking person  = ?

Solution:

To solve this problem;

    Speed  = \frac{distance}{time taken}

  Time taken should be in seconds;

                 1 min   =  60s

                 20min  = 20 x 60  = 1200s

Speed  = \frac{1000}{1200}   = 0.83m/s

8 0
3 years ago
A sports car accelerates at a constant rate from rest to a speed of 90 km/hr in 8 s. What is its acceleration?
AfilCa [17]
First convert 90km/hr to m/s.

Initiate velocity = 0m/s (car was at rest)

Final velocity is 25m/s (90km/hr converted)

25m/s - 0m/s / 8s = 3.125 m/s^s

Therefore the answer is option A (3.13m/s^2)
3 0
3 years ago
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