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astra-53 [7]
3 years ago
13

Help me with this question please

Physics
1 answer:
svp [43]3 years ago
5 0
10 11 12 10 18
14 16 12 13 13
13 14 15 13 13
8 10 16 16 13
They're all in the same order as the paper
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What strength can accurately be attributed to the force of the throw?
ohaa [14]
Well for example if you’re throwing a ball The force that moves the ball "up"
must overcome (be larger than) the downward force of the ball's weight.
Once the upward "force of the throw" overcomes the weight, it must then accelerate the ball upward, in order to give an initial upward speed.
Newton's formula: Fnet = ma
indicates that the acceleration (a) will equal the *excess upward force* {once the weight force is cancelled} divided by the ball's mass.
so in summary:
Fnet in Newtons will be the child's UPward force minus the ball's weight.
3 0
4 years ago
A tennis ball is thrown upwards from the edge of a cliff with a speed of 10\,\dfrac{\text m}{\text s}10 s m ​ 10, start fraction
tresset_1 [31]

Answer:

5.1m

Explanation:

Given the following parameters

Speed v = 10m/s

Time = 3.0s

Required

Displacement of the tennis ball

Using the equation of motion

v² =u²-2gh (g i s negative due to upward motion of the ball)

Substitute the given values into the expression above;

0² = 10²-2(9.8)h

0 = 100-19.6h

19.6h = 100

h = 100/19.6

h= 5.1m

Hence the displacement of the ball is 5.1m

5 0
3 years ago
Sudhir walks 0.40 km in a direction 60.0° west of north, then goes 0.50 km due west. What is his displacement?
Gemiola [76]

Answer:

The displacement of Sudhir is 0.781 km.

Explanation:

Given;

initial distance, d₁ = 0.4 km = 400 m, N60.0°W

final distance, d₂ = 0.5 km

Make a sketch of Sudhir motion to form a right angled triangle;

(Check image uploaded).

Apply cosine rule to determine d "displacement"

d² = 500² + 400² - (2 x 500 x 400 x cos 120)

d² = 410,000 - (400,000 x -0.5)

d² = 410,000 - (-200,000)

d² = 410,000  + 200,000

d² = 610,000

d = √610000

d = 781.03 m

d = 0.781 km

Therefore, the displacement of Sudhir is 0.781 km.

8 0
3 years ago
A measure of change in velocity in a measure of time is
klemol [59]

\\ \sf\Rrightarrow Acceleration=\dfrac{\Delta V}{t}[)tex]In simplified form[tex]\\ \sf\Rrightarrow Acceleration=\dfrac{dv}{dt}

  • The rate of change of velocity with respect to time period is called acceleration.
  • SI units-m/s^2
8 0
3 years ago
The density of blood is 1.05 kg/m3, find the mass of a bag of blood for a transfusion, if the volume is 1.5 m3.
hoa [83]

(1.5 m^3) • (1.05 kg/m^3) = 1.575 kg.  That's quite a bag you've got there !  1 m^3 is like 264 gallons of blood.  Hope the poor patient survives the transfusion. Also, the actual density of blood is around 1.05 g/cm^3, or 1050 kg/m^3. The blood they're giving the guy in this question is about 18% less dense than the AIR in his hospital room, and they're pumping 264 gallons of it into him. Maybe THAT'S his whole problem.

6 0
3 years ago
Read 2 more answers
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