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3 years ago

Which formulas represent ionic compounds and which represent covalent compounds?

Chemistry

1 answer:

Free_Kalibri [48]3 years ago

5 0

Answer:

See answer below

Explanation:

This is pretty easy to solve. First you need to understand that an ionic compound is usually formed between a metal and a non metal. This usually happens between elements from group 1 through group 10 or 11 of the periodic table. A covalent compound is always given in non metal elements from the periodic table, and it's usually the elements from group 13 through group 17.

Some compounds there are missing some atoms, but I manage to find this question and saw the atoms missing, so, in my answer you will see the corrected compound. so don't be surprised.

According to what I state above, then the covalent compounds are:

C₆H₅N

PCl₃

C₂H₄O

NH₃

N₂

SO₄²⁻

The ionic compounds are:

CaO

CdBr₂

WO₂

Na₂O

CsF

Hope this helps

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What is the answer please tell me

Nastasia [14]

Answer:

you need to include the bottom portion, not enough info

Explanation:

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3 years ago

Consider the nuclear equation below. Superscript 235 subscript 92 upper U right arrow superscript 4 subscript 2 upper H e. What

coldgirl [10]

Answer:

$\rm_{90}^{231}\text{Th}$

Explanation:

The unbalanced nuclear equation is

$\rm _{92}^{235}\text{U} \longrightarrow \, _{2}^{4}\text{He} + X$

Let's write X as a nuclear symbol.

$\rm _{92}^{235}\text{U} \longrightarrow \, _{2}^{4}\text{He} + _{Z}^{A}\text{X}$

The main point to remember in balancing nuclear equations is that the sums of the superscripts and of the subscripts must be the same on each side of the reaction arrow.

Then

235 = 4 + A , so A = 235 - 4 = 231, and

92 = 2 + Z , so Z = 92 - 2 = 90

And your nuclear equation becomes

$\rm _{92}^{235}\text{U} \longrightarrow \, _{2}^{4}\text{He} +\, _{90}^{231}\text{X}$

Element 90 is thorium, so

$\rm X = _{90}^{231}\text{Th}$

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Answer:
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Explanation:
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Answer:

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Explanation: hope this answers your question

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2 years ago