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Artist 52 [7]
3 years ago
15

Which formulas represent ionic compounds and which represent covalent compounds?

Chemistry
1 answer:
Free_Kalibri [48]3 years ago
5 0

Answer:

See answer below

Explanation:

This is pretty easy to solve. First you need to understand that an ionic compound is usually formed between a metal and a non metal. This usually happens between elements from group 1 through group 10 or 11 of the periodic table. A covalent compound is always given in non metal elements from the periodic table, and it's usually the elements from group 13 through group 17.

Some compounds there are missing some atoms, but I manage to find this question and saw the atoms missing, so, in my answer you will see the corrected compound. so don't be surprised.

According to what I state above, then the covalent compounds are:

C₆H₅N

PCl₃

C₂H₄O

NH₃

N₂

SO₄²⁻

The ionic compounds are:

CaO

CdBr₂

WO₂

Na₂O

CsF

Hope this helps

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Complete the kw expression for the autoionization of water.
DochEvi [55]
<span>Kw = water autoionization constant=1.0 x 10-14 @ 25 °C Kw = [H3O+] [OH¯] 1.0 x 10-14= [x][x] x=1.00 x 10¯7 M</span>
3 0
3 years ago
If a steel container holds 3.50 moles of hydrogen gas and 3.50 moles of helium gas, and the total pressure is 4.00 atm., what is
Sunny_sXe [5.5K]

Answer:

1. Partial pressure of H₂ = 2 atm

2. Partial pressure of He = 2 atm

Explanation:

The following data were obtained from the question:

Mole of H₂ = 3.50 moles

Mole of He = 3.50 moles

Total pressure (Pₜ) = 4 atm

Partial pressure of H₂ =?

Partial pressure of He =?

Next, we shall determine the mole fraction of each gas this can be obtained as follow:

Mole of H₂ = 3.50 moles

Mole of He = 3.50 moles

Total mole = Mole of H₂ + Mole of He

Total mole = 3.50 + 3.50

Total mole = 7 moles

Mole fraction of H₂ = mole of H₂ / Total mole

Mole fraction of H₂ = 3.5/7

Mole fraction of H₂ = 0.5

Mole fraction of He = mole of He / Total mole

Mole fraction of He = 3.5/7

Mole fraction of He = 0.5

1. Determination of the partial pressure of H₂.

Mole fraction of H₂ = 0.5

Total pressure (Pₜ) = 4 atm

Partial pressure of H₂ =?

Partial pressure of H₂ = Mole fraction of H₂ × Pₜ

Partial pressure of H₂ = 0.5 × 4

Partial pressure of H₂ = 2 atm

2. Determination of the partial pressure of He.

Total pressure (Pₜ) = 4 atm

Partial pressure of H₂ = 2 atm

Partial pressure of He =?

Total pressure (Pₜ) = Partial pressure of H₂ + Partial pressure of He

4 = 2 + Partial pressure of He

Collect like terms

Partial pressure of He = 4 – 2

Partial pressure of He = 2 atm

6 0
3 years ago
Calculate the formula unit mass of Sodium hydroxide.
Ksivusya [100]

Answer:

MNa=22.989 g/mol.

MO=15.999 g/mol.

MH=1.0079 g/mol

4 0
3 years ago
Some nighttime partygoers wear glow-inthe-dark necklaces. the necklaces start glowing once they are ""activated"" by snapping th
8_murik_8 [283]

Answer:

Exergonic

Explanation:

The process is exergonic because it transfer energy from the system to the surrounds in the shape of light. It happens because of the Gibbs free energy (ΔG) which is lower than zero. If the reaction was Endergonic, the Gibbs free energy should be higher than zero. We can calculate it from the GIbbs-Helmholtz equation: ΔG = ΔH - T . ΔS. ΔH is enthalpy, T is the temperature and ΔS is entropy.

5 0
3 years ago
A buffer solution contains 0.496 M KHCO3 and 0.340 M K2CO3. If 0.0585 moles of potassium hydroxide are added to 250. mL of this
aev [14]

Answer:

pH = 10.9

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to say that the undergoing reaction between this buffer and OH⁻ promotes the formation of more CO₃²⁻ because it acts as the base, we can do the following:

n_{CO_3^{2-}}=0.34mol/L*0.250L+0.0585mol=0.1435mol\\\\n_{HCO_3^{-}}=0.34mol/L*0.250L-0.0585mol=0.0265mol

The resulting concentrations are:

[CO_3^{2-}]=\frac{0.1435mol}{0.25L}=0.574M \\

[HCO_3^{-}]=\frac{0.0265mol}{0.25L}=0.106M

Thus, since the pKa of this buffer system is 10.2, the change in the pH would be:

pH=10.2+log(\frac{0.574M}{0.106M} )\\\\pH=10.9

Which makes sense since basic OH⁻ ions were added.

Regards!

6 0
4 years ago
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