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Viktor [21]
3 years ago
11

Which of the following describes an element that is reduced in a reaction? It acts in the reactant that is the reducing agent. I

t has a decrease in its oxidation number. Cd yields Cd2+ + 2e− Zn + Cu2+ yields Zn2+ + Cu
Chemistry
1 answer:
stiks02 [169]3 years ago
4 0
It has a decrease in oxidation number

The process of reduction is when the oxidation number of a chemical specie is lowered, or when the specie gains electrons. A chemical specie undergoing reduction will act as an oxidizing agent, because it will oxidize the other reactant by itself getting reduced.
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If a cold piece of metal is added to hot water, the water will
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Over time the metal will cool and the water will heat up. Eventually the two objects will have the same temperature

Explanation:

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In the following reactions identify which substances are solid (s) or aqueous (aq). 1. Li,SO4( aq ) + MgCl, ( aq ) - 2LICI ( 2LI
IrinaK [193]

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Ok

Explanation:

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2 years ago
What is atom?????????????
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g For the following reaction, 0.500 moles of silver nitrate are mixed with 0.285 moles of copper(II) chloride. What is the formu
scZoUnD [109]

Answer:

CuCl_2 is the formula for the limiting reagent.

Mass of silver chloride produced is 71.8 g.

Explanation:

CuCl_2+2AgNO_3\rightarrow 2AgCl+Cu(NO_3)_2

Moles of silver nitrate = 0.500 mol

Moles of copper(II) chloride = 0.285 mol

According to reaction, 2 moles of silver nitrate reacts with 1 mole of copper chloride , then 0.500 mole of silver nitrate will react with :

\frac{1}{2}\times 0.500 mol=0.250 mol of copper(II) chloride

As we can see that moles of copper(II) chloride will be reacting is 0.250 mol less than present moles of copper (II) chloride ,so this means that silver nitrate is limiting reagent.

And moles of silver chloride to be formed will depend upon silver nitrate.

According to reaction, 2 moles of silver nitrate gives 2 moles of silver chloride , then 0.500 mole of silver nitrate will give  :

\frac{2}{2}\times 0.500 mol=0.500 mol of silver chloride

Mass of silver chloride produced:

0.500 mol × 143.5 g/mol = 71.8 g

7 0
3 years ago
Naomi is investigating the properties of a solid material. It takes 120 joules to raise the temperature of 10 grams of the mater
MrRissso [65]
When heat energy is supplied to a material it can raise the temperature of mass of the material.
Specific heat is the amount of energy required by 1 g of material to raise the temperature by 1 °C.
equation is 
H = mcΔt
H - heat energy 
m - mass of material 
c - specific heat of the material 
Δt - change in temperature
substituting the values in the equation 
120 J = 10 g x c x 5 °C
c = 2.4 Jg⁻¹°C⁻¹
3 0
3 years ago
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