Question

During this reaction, P4 + 5O2 → P4O10, 1.5 moles of product were made in seconds. What is the rate of reaction? 0.011 g/min 210 g/min 380 g/min 850 g/min

Answer 1

The answer is: the rate of reaction is 850 g/min.

n(P₄O₁₀) = 1.5 mol; amount of product.

M(P₄O₁₀) = 283.9 g/mol; molar mass of phosphorus(V) oxide.

m(P₄O₁₀) = n(P₄O₁₀) · M(P₄O₁₀).

m(P₄O₁₀) = 1.5 mol · 283.9 g/mol.

m(P₄O₁₀) = 425.85 g in 30 seconds.

Make proportion: 425 g : 30 s = m(P₄O₁₀) : 60 s.

m(P₄O₁₀) = 850 g in 60 s.

Answer 2

Answer:

850

Explanation: