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PilotLPTM [1.2K]
4 years ago
14

Pls help asap...

Chemistry
1 answer:
Dmitriy789 [7]4 years ago
7 0
The answer to this question would be <span>repeatable and verifiable. If the result of the research can't be repeated then you can't deduce anything from it. The result should be verified so no one can falsify a claim of observation.

Morality and the inexpensive shouldn't be mandatory.</span>
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Which type of reaction?
polet [3.4K]
condensation polymerization, since a byproduct of the reaction is a single molecule of water (hence condensation of water)

addition polymerization is if you add the two polymers together like blocks and should have no byproducts

esterification is when you combine an organic acid with an alcohol. Since neither of the two polymers look like acids, you can rule this out.

never heard of saponification, Im an mechanical engineer not an organic chemist

3 0
3 years ago
A 112. 6 g mass of unknown material is submersed in 102 ml of water to yield a final volume of 126 ml. What is the apparent dens
skad [1K]

The density of the unknown material is 0.213 ml/g

<h3>Apparent density of the unknown material</h3>

The apparent density of the unknown material is calculated as follows;

Volume of the unknown substance = 126 ml - 102 ml = 24 ml

Density of the unknown substance = mass/volume

Density of the unknown substance =  24 ml / 112.6 g

Density of the unknown substance = 0.213 ml/g

Thus, the density of the unknown material is 0.213 ml/g

Learn more about density here; brainly.com/question/6838128

#SPJ1                          

4 0
1 year ago
Help me nowww please and thanks
kati45 [8]

The answer to your question is Gallium, or GA. The trick is to always check if they are along the same vertical column. This indicates that they have the same Valence electrons, which is involved in all the bonding and define the electronegative status of the atom.

4 0
3 years ago
Read 2 more answers
For each of the following balanced oxidation-reduction reactions, (i) identify the oxidation numbers for all the elements in the
AlladinOne [14]

Answer:

<h3>1. 10 e⁻</h3>

Oxidation numbers

I₂O₅(s): I (5+); O(2-)

CO(g): C(2+); O(2-)

I₂(s): I(0)

CO₂(g): C(4+); O(2-)

<h3>2. 4 e⁻</h3>

Oxidation numbers

Hg²⁺(aq): Hg(2+)

N₂H₄(aq): N(2-); H(1+)

Hg(l): Hg(0)

N₂(g): N(0)

H⁺(aq): H(1+)

<h3>3. 6 e⁻</h3>

Oxidation numbers

H₂S(aq): H(1+); S(2-)

H⁺(aq): H(1+)

NO₃⁻(aq): N(5+); O(2-)

S(s): S(0)

NO(g): N(2+); O(2-)

H₂O(l): H(1+); O(2-)

Explanation:

In order to state the total number of electrons transferred we have to identify both half-reactions for each redox reaction.

1.  I₂O₅(s) + 5 CO(g) → I₂(s) + 5 CO₂(g)

Oxidation: 10 e⁻ + 10 H⁺(aq) + I₂O₅(s) → I₂(s) + 5 H₂O(l)

Reduction: 5 H₂O(l) + 5 CO(g) → 5 CO₂(g) + 10 H⁺(aq) + 10 e⁻

2. 2 Hg²⁺(aq) + N₂H₄(aq) → 2 Hg(l) + N₂(g) + 4 H⁺(aq)

Oxidation: N₂H₄(aq) → N₂(g) + 4 H⁺(aq) + 4 e⁻

Reduction: 2 Hg²⁺(aq) + 4 e⁻ → 2 Hg(l)

3. 3 H₂S(aq) + 2H⁺(aq) + 2 NO₃⁻(aq) → 3 S(s) + 2 NO(g) + 4H₂O(l)

Oxidation: 3 H₂S(aq) → 3 S(s) + 6 H⁺(aq) + 6 e⁻

Reduction: 8 H⁺(aq) + 2 NO₃⁻(aq) + 6 e⁻ → 2 NO(g) + 4 H₂O

5 0
3 years ago
To make sure that the white powder was all sodium chloride and not mixed with sodium hydrogen carbonate, would you need to add a
TiliK225 [7]

Answer: i hope you thought this was an actual answer

Explanation:

6 0
3 years ago
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