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gladu [14]
3 years ago
5

when you burn 2 L of propane (C3H8) at stp , you find 5.6L of carbon dioxide has been produced what is the percent yeild

Chemistry
1 answer:
Oksanka [162]3 years ago
7 0

Answer:

93%

Explanation:

First write the balanced reaction

C3H8 + 5O2 --> 3CO2 +4H2O

2nd, find the theoretical yield

2L C3H8 (1mol/22.4L) (3 mol CO2/1 molC3H8) (22.4 L/ 1mol) = 6L

3rd, Find percent yield

%yield = (actual / theoretical) x100 = (5.7/6) x 100 = 93%

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Answer:

The answer to your question is

                                        4C₇H₁₇  + 45 O₂    ⇒   28 CO₂   +  34H₂O  

Explanation:

Write the equation

                                        C₇H₁₇  +    O₂    ⇒    CO₂   +    H₂O  

Process

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                                 Reactants            Element              Products

                                        7                          C                           1

                                       17                          H                          2

                                        2                          O                          3

As the number of reactants and products is different, we conclude that the reaction is unbalanced.

2.- Write a coefficient "7" to CO₂   and a coefficient of 17/2 to H₂O

                                      C₇H₁₇  +    O₂    ⇒   7CO₂   +  \frac{17}{2}H₂O  

                                 Reactants            Element              Products

                                        7                          C                           7

                                       17                          H                          17

                                        2                          O                          51/2

3.- Write a coefficient of 45/2 to the O₂, and multiply all the equation by 2.

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                        68                          H                        68

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