Answer:
<em>The answer is 200</em>
Step-by-step explanation:
<em>To solve the question given, let us recall the following,</em>
<em>Let r4=200 miles apart</em>
<em>r=50 mph combined speed
</em>
<em>Where </em>
<em>2f+10=50
</em>
<em>2f=40
</em>
<em>f=20
</em>
<em>f+10=30
</em>
<em>or we can express it in another way,</em>
<em>which is</em>
<em>f x4+(f+10)x 4=200
</em>
<em>f x4+f x4+40=200
</em>
<em>8f+40=200</em>
<em>Then</em>
<em>8f is =160
</em>
<em>f=20
</em>
<em>f+10=30
</em>
<em>Therefore,</em>
<em>4x 20+4 x 30=200
</em>
<em>80+120=200
</em>
<em>200=200</em>
<em />
Answer:
100.9 yards
Step-by-step explanation:
One circuit of the track is a distance of ...
C = 2πr = 2π(60 yd) = 120π yd.
At Alex's running rate, the distance covered in 20 minutes is ...
(4 yd/s)(20 min)(60 s/min) = 4800 yd
The number of circuits will be ...
(4800 yd)/(120π yd/circuit) = 40/π circuits ≈ 12.7324 circuits
The last of Alex's laps is more than half-completed, so the shortest distance to his starting point is 13 -12.7324 = 0.2676 circuits,
That distance is (0.2676 circuits)×(120π yd/circuit) ≈ 100.88 yd
The shortest distance along the track to Alex's starting point is about 100.9 yards.
_____
<em>Additional comment</em>
The exact distance is 120(13π-40) yards. The distance will vary according to your approximation for pi. If you use 3.14, this is about 98.4 yards.
Im not sure if it’s right but I think it’s -6,17
Answer:invalid
Step-by-step explanation:
