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loris [4]
3 years ago
15

3) How much energy does it take to condense 26.5 g of H0 at 100°C? Equation:

Chemistry
1 answer:
andreyandreev [35.5K]3 years ago
8 0

Answer:

59.89 KJ

Explanation:

Data Given:

mass of H₂O (m) = 26.5 g

heat released (Q) = ?

Solution:

This question is related to the latent heat of condensation.

Latent heat of condensation is the amount of heat released when water vapors condenses to liquid.

Formula used

Q = m x Lc . . . . . (1)

where

Lc = specific latent heat of condensation

Latent heat of vaporization of water is exactly equal to heat of condensation with -ve charge

So, Latent heat of vaporization of water has a constant value

Latent heat of vaporization of water = 2260 J/g

So

Latent heat of condensation of water will be = - 2260 J/g

Put values in eq. 1

            Q = (26.5 g) x (- 2260 J/g)

            Q = - 59890 J

convert J to kJ

1000 J = 1 KJ

59890 J = 59890 / 1000 = 59.89 KJ

So, 59.89 K of heat will be released. negative sign indicate release of energy for condensation

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1. Baking powder is a 1:1 molar mixture of cream of tartar (KHC4H4O6) and baking soda (NaHCO3). A recipe calls for two teaspoons
olasank [31]

Answer:

3.57 g.

Explanation:

  • The ratio of cream of tartar (KHC₄H₄O₆) to baking soda (NaHCO₃) in the baking powder is 1:1.
  • We need to calculate the number of moles of (8.0 g) of cream of tartar (KHC₄H₄O₆) using the relation:<em> n = mass / molar mass,</em>

mass of cream of tartar (KHC₄H₄O₆) = 8.0 g.

molar mass of cream of tartar (KHC₄H₄O₆) = 188.1772 g/mol.

∴ n of cream of tartar (KHC₄H₄O₆) = mass /molar mass = (8.0 g) / (188.1772 g/mol) = 0.0425 mol.

  • Since the mole ratio of the two components is 1:1, the no. of moles of baking soda (NaHCO₃) should be added is 0.0425 mol.
  • The quantity of baking soda (NaHCO₃) can be calculated using the relation:

mass = n x molar mass = (0.0425 mol)(84.007 g/mol) = 3.57 g.

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3 years ago
If only one-fourth the amount of brown sugar in the recipe were used, how much brown sugar would be used?
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1.) Over the hour before the precipitation started falling where it did?
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Those are the answers to an unknown question???

Explanation:

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Dolomite is a mixed carbonate of calcium and magnesium. Calcium and magnesium carbonates both decompose upon heating to produce
Setler79 [48]

Answer:

72.03 %

Explanation:

Total mass of dolomite = 9.66 g

Let the mass of Magnesium carbonate = x g

The mass of calcium carbonate = 9.66 - x g

Calculation of the moles of Magnesium carbonate as:-

Molar mass of Magnesium carbonate = 122.44 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{x\ g}{84.3139\ g/mol}=\frac{x}{84.3139}\ mol

Calculation of the moles of calcium carbonate as:-

Molar mass of calcium carbonate = 100.0869 g/mol

Thus,

Moles= \frac{9.66 - x\ g}{100.0869\ g/mol}=\frac{9.66 - x}{100.0869}\ mol

According to the reaction shown below:-

MgCO_3\rightarrow MgO+CO_2

CaCO_3\rightarrow CaO+CO_2

In both the cases, the oxides formed from the carbonates in the 1:1 ratio.

So, Moles of MgO = \frac{x}{84.3139}\ mol

Molar mass of MgO = 40.3044 g/mol

Thus, Mass = Moles*Molar mass = \frac{x}{84.3139}\times 40.3044 \ g

Moles of CaO = \frac{9.66 - x}{100.0869}\ mol

Molar mass of CaO = 56.0774 g/mol

Thus, Mass = Moles*Molar mass = \frac{9.66 - x}{100.0869}\times 56.0774 \ g

Given that total mass of the oxide = 4.84 g

Thus,

\frac{x}{84.3139}\times 40.3044 +\frac{9.66 - x}{100.0869}\times 56.0774=4.84

\frac{40.3044x}{84.3139}+56.0774\times \frac{-x+9.66}{100.0869}=4.84

-694.1618435x+45673.48749\dots =40843.38968\dots

x=\frac{4830.09780\dots }{694.1618435}

x=6.9582

Thus, the mass of Magnesium carbonate = 6.9582 g

\%\ mass=\frac{Mass_{MgCO_3}}{Total\ mass}\times 100

\%\ mass=\frac{6.9582}{9.66}\times 100=72.03\ \%

3 0
3 years ago
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