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guapka [62]
3 years ago
7

Chemistry problem? Joey claims that Oxygen 16 and Nitrogen 16 are identical. Compare and contrast Oxygen 16 and Nitrogen 16. Ple

ase be descriptive.
Chemistry
1 answer:
8_murik_8 [283]3 years ago
3 0
oxygen 16 is a stable isotope and has a natural abundance of 99.762% 

nitrogen 16 is an unstable isotope with a half life of 7.13 seconds meaning it is nearly nonexistent

joey is probably thinking of nitrogen 14 which is a stable isotope and has a natural abundance of 99.6%

oxygen 16 - 
<span>https://en.wikipedia.org/wiki/Isotopes_of_oxygen
</span><span>nitrogen 16/14 - https://education.jlab.org/itselemental/iso007.html</span>

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2.
katovenus [111]

Answer:

A. 6atm

Explanation:

Using pressure law equation:

P1/T1 = P2/T2

Where;

P1 = initial pressure (atm)

T1 = initial temperature (K)

P2 = final pressure (atm)

T2 = final temperature (K)

According to this question;

P1 = 3 atm

P2 = ?

T1 = 120K

T2 = 240K

Using P1/T1 = P2/T2

3/120 = P2/240

Cross multiply

240 × 3 = P2 × 120

720 = 120P2

P2 = 720/120

P2 = 6atm

4 0
3 years ago
A salt is best described as a compound that is formed from the reaction between
kaheart [24]

Answer:

b

Explanation:

5 0
4 years ago
E
Nana76 [90]
Hey :)

Air pollution

Hope this helps!

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7 0
4 years ago
Read 2 more answers
El agua del mar contiene aproximadamente un 3,0 % m/v de sal (NaCl, 58,44 g/mol), (asuma que es la única fuente de cloruros) si
Alchen [17]

Answer:

s = 4.41 g/L.

Explanation:

¡Hola!

En este caso, considerando el escenario dado, se hace necesario para nosotros saber que la posible reacción de disociación la experimenta el cloruro de plomo (II) como se muestra a continuación:

PbCl_2(s)\rightleftharpoons 2Cl^-(aq)+Pb^{2+}(aq)

Lo cual hace que la expresión de equilibrio se calcule como:

Ksp=[Pb^{2+}][Cl^-]^2

Y que en términos de la solubilidad molar, s, se resuelve como:

1.6x10^{-5}=s(2s)^2\\\\1.6x10^{-5}=4s^3\\\\s=\sqrt[3]{\frac{1.6x10^{-5}}{4} } \\\\s=0.0159molPbCl_2/L

Ahora, convertimos este valor a g/L al multiplicarlo por la masa molar del cloruro de plomo (II):

s=0.0159molPbCl_2/L*\frac{278.1gmolPbCl_2}{1molmolPbCl_2} \\\\s=4.41g/L

¡Saludos!

7 0
3 years ago
Which branch of chemistry would study how pollution effects marine life?
mart [117]

Answer: (D) environmental chemistry

Explanation:

8 0
3 years ago
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