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salantis [7]
3 years ago
7

Activity 3: Under Pressure<br /><br />Q.7 What did you observe in each bottle<br />Q.8 Explain your observatio

n.<br />Q.9 What is the role of hot water in the setup?<br /><br />Q.10 Do you have the same observation as in the softdrinks?<br />Q.11 Explain your answer.<br /><br />Pa help po
Physics
2 answers:
valina [46]3 years ago
7 0

Q7. A fizzing sound was overheard shadowed by the rushing out of bubbles from the bottle dipped in hot water. There was also a sound perceived in the bottle to be found in cold water but not as much as in bottle A.

Q8. There was amassed gas inside the bottle.

Q9. The hot water surges the temperature of the soda drink inside the bottle. As the temperature increases, more gas is accumulated inside the bottle. This reasons the fizzing sound.

Q10. The observation in the bottle of cooking oil is not the same as in the soda drinks.

<span>Q11. There was little gas out in the bottle of cooking oil for the reason of its structure. We know that soda drink is carbonated. The great temperature free the gas from the soda drinks.</span>

Luda [366]3 years ago
4 0

Answer no 7. A fizzing sound was overheard shadowed by the rushing out of bubbles from the bottle dipped in plight. There was also a sound perceived within the bottle to be found in cold water but not the maximum amount as in bottle A.

Answer no 8. There was amassed gas inside the bottle.

Answer no 9. the new water surges the temperature of the soda drink inside the bottle. because the temperature increases, more gas is accumulated inside the bottle. This reasons the fizzing sound.

Answer no 10. The observation within the bottle of vegetable oil isn't the identical as within the soda drinks.

Answer no 11. There was little gas get in the bottle of vegetable oil for the rationale of its structure. we all know that soda drink is carbonated. the good temperature free the gas from the soda drinks.

<h2>Further Explanation </h2>

State equations are thermodynamic equations that describe the state of matter under a set of physical conditions. A state equation is a constitutive equation that provides a mathematical relationship between two or more state functions related to the matter, such as temperature, pressure, volume, and internal energy. State equations are useful in describing the properties of fluids, fluid mixtures, solids, and even the inside of a star.

The most common use of a state equation is in predicting the state of gases and liquids. One of the simplest state equations in this use is the ideal gas law, which is quite accurate in predicting the state of the gas at low pressure and high temperature. But this equation becomes increasingly inaccurate at higher pressures and lower temperatures and fails to predict condensation from gases to liquids. However, several more accurate state equations have been developed for various gases and liquids. At present, there is no single state equation that can accurately estimate the properties of all substances under all conditions.

The ideal gas equation is the state equation of an ideal gas. This equation is a good approach to the characteristics of some gases under certain conditions. This equation was first coined by Émile Clapeyron in 1834 as a combination of Boyle's Law and Charles's Law. This equation is commonly written as

PV = nRT

where P is the absolute pressure on the gas, V is the volume, n is the number of particles in the gas (in moles), T is the temperature in kelvin units, and R is the ideal gas constant, which is 0.08205 L atm mol-1 K-1.

This equation can also be derived from kinetic theory, which was coined separately by August Krönig in 1856 and Rudolf Clausius in 1857. Universal gas constants were discovered and first introduced to the ideal gas law by Dmitri Mendeleev in 1874. The ideal gas equation is useful, especially in gas stoichiometry.

Learn more

definition of The ideal gas equation brainly.com/question/7183242

definition of State equations brainly.com/question/7183242

Details

Grade: High School

Subject: Physics

keywords: State equations, The ideal gas equation

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A motorcycle accelerates uniformly from rest and reaches a linear speed of 24.8 m/s in a time of 9.87 s. The radius of each tire
Vinvika [58]

Answer:

8.756 rad/s²

Explanation:

Given that:

A motorcycle accelerates uniformly from rest, then initial velocity v_i = 0 m/s

It final velocity v_f = 24.8 m/s

time (t) = 9.87 s

radius (r) of each tire  = 0.287 m

Firstly; the linear acceleration of the motor cycle  is determined as follows:

a_T =(V_f - v_i)/t

=(24.8-0)/9.87

=2.513 m/s²

Then;  the magnitude of angular acceleration

α =a_T /r

=2.513/0.287

=8.756 rad/s²

6 0
3 years ago
Read 2 more answers
A person jumps from the roof of a house 3.5-m high. When he strikes the ground below, he bends his knees so that his torso decel
Korvikt [17]

The force exerted on his torso by his legs during the deceleration is 4365 N.

<u>Explanation:</u>

Mass of the torso m=45kg

Height of the building s=3.5 m

Decelerating distance=0.71 m

when he jumps to the ground, the only acceleration is acceleration due to gravity g

<u>motion1 from top to ground </u>

initial velocity u=0

we have to calculate final velocity v using the following equation of motion.

v^2-u^2=2gs\\v^2-0^2=2\times 9.8\times3.5=68.6\\v=\sqrt{68.6} \\=8.3

use height of the building as the distance s as the jump from top to the ground is only described here.

<u>Motion 2 on the ground</u>

v=0

u=8.3(final  velocity of motion 1)

The deceleration after striking the ground can  be calculated from the equation of motion

v^2-u^2=2as\\\\a=v^2-u^2/2\times 0.71\\=0^2-8.3^2/0.71=97 m/s^2

The decelerating distance is used in the place of s since since the motion after hitting the ground is described in this case.

The equation of force is

F=ma\\=45\times 97=4365 N

6 0
3 years ago
Help me please
agasfer [191]

Answer:

For a velocity versus time graph how do you know what the velocity is at a certain  time?

Ans: By drawing a line parallel to the y axis (Velocity axis) and perpendicular to the co-ordinate of the Time on the x axis (Time Axis). The point on the slope of the graph where this line intersects, will be the desired velocity at the certain time.

_____________________________________________________

How do you know the acceleration at a certain time?

Ans: We\ know\ that\ acceleration = \frac{Final\ velocity-Initial\ Velocity}{Time\ taken}

Hence,

By dividing the difference of the Final and Initial Velocity by the Time Taken, we could find the acceleration.

_________________________________________________________

How do you know the  Displacement at a certain time?

Ans: As Displacement equals to the area enclosed by the slope of the Velocity-Time Graph, By finding the area under the slope till the perpendicular at the desired time, we find the Displacement.

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4 0
3 years ago
Helium balloons pop in a hot car because
lukranit [14]

Answer:

This is because helium molecules get bigger when they heat up , so if your balloons keep getting hotter , they will eventually pop

5 0
3 years ago
Read 2 more answers
Caculate the component of a force of 200 ns <br>at a direction of 60° to the force​
Lady bird [3.3K]

Answer:

F_x = 100N

F_y = 100\sqrt 3 \ N

Explanation:

Given

F = 200N

\theta = 60^o

Required

The component of the force in F direction

To do this, we simply calculate the force in the vertical and horizontal direction.

This is calculated as:

F_x = F * \cos(\theta) --- Horizontal

F_y = F * \cos(\theta) ---- Vertical

So, we have:

F_x = F * \cos(\theta) --- Horizontal

F_x = 200N * \cos(60^o)

F_x = 200N * 0.5

F_x = 100N

F_y = F * \cos(\theta) ---- Vertical

F_y = 200N * \sin(60^o)

F_y = 200N * \frac{\sqrt 3}{2}

F_y = 100\sqrt 3 \ N

7 0
3 years ago
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