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Andrew [12]
2 years ago
8

When must scientific theories be changed

Physics
1 answer:
madreJ [45]2 years ago
4 0

Answer:

when new information disproving the current theory becomes available.

Explanation:

hope this helps..

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On a straight horizontal track along which blocks can slide with negligible friction, block 1 slides toward block 2, which is in
vivado [14]

If the mass and post-collision speed of block 1 is known, the momentum of the block 2 can be determined.

<h3>What is momentum?</h3>

The momentum of an object in motion is the product of mass and speed of the object.

P = mv

<h3>Conservation of linear momentum</h3>

The principle of conservation of linear momentum states that, the sum of the initial momentum must be equal to the sum of the final momentum.

m_1v_1 = m_2 v_2

Thus, if the mass and post-collision speed of block 1 is known, the momentum of the block 2 can be determined.

Learn more about conservation of linear momentum here: brainly.com/question/7538238

7 0
2 years ago
What information does a line graph show
ikadub [295]
Line graphs tend to show a change in data over time.
7 0
3 years ago
An emf is induced by rotating a 1060 turn, 20.0 cm diameter coil in the Earth's 5.25 ✕ 10−5 T magnetic field. What average emf (
lara31 [8.8K]

Answer:

The average emf induced in the coil is 175 mV

Explanation:

Given;

number of turns of the coil, N = 1060 turns

diameter of the coil, d = 20.0 cm = 0.2 m

magnitude of the magnetic field,  B = 5.25 x 10⁻⁵ T

duration of change in field, t = 10 ms = 10 x 10⁻³ s

The average emf induced in the coil is given by;

E = N\frac{\delta \phi}{dt} \\\\E = N\frac{\delta B}{\delta t}A

where;

A is the area of the coil

A = πr²

r is the radius of the coil = 0.2 /2 = 0.1 m

A = π(0.1)² = 0.03142 m²

E = \frac{NBA}{t} \\\\E = \frac{1060*5.25*10^{-5}*0.03142}{10*10^{-3}} \\\\E = 0.175 \ V\\\\E = 175 \ mV

Therefore, the average emf induced in the coil is 175 mV

3 0
3 years ago
Which of the following is true of the atom below:
Brilliant_brown [7]

Its B. I know because I just took the test in K12 so your welcome EJ.

7 0
3 years ago
A wire of length 26.0 cm carrying a current of 5.77 mA is to be formed into a circular coil and placed in a uniform magnetic fie
Olin [163]

Answer:

The maximum torque is  \tau_{max} =  1.139 *10^{-7} \ N \cdot m

Explanation:

From the question we are told that

   The length of the wire is  l =  26.0 \ cm  =  0.26 \  m

     The current flowing through the wire is  I  = 5.77mA  =  5.77 *10^{-3} \ A

      The magnetic field is  B = 3.67 \ mT  =  3.67 *10^{-3 } T

         

The maximum torque is mathematically evaluated as

        \tau_{max} =   \mu B  

Where \mu  is the magnetic dipole moment which is mathematically represented as

        \mu  =  \frac{I l^2}{4 \pi n }

Where n is the number of turns which from the question is  1

    substituting values

       \mu  =  \frac{ 5.77 *10^{-3}  *  0.26^2}{4  * 3.142* 1 }

     \mu  =  3.10 4*  10^{-5}  A m^2

Now  

      \tau_{max} =  3.104 *10^{-5} * 3.67 *10^{-3}  

      \tau_{max} =  1.139 *10^{-7} \ N \cdot m  

7 0
3 years ago
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