Answer:
the girl's displacement in both magnitude and direction is 7.81 m at 50.2⁰ North west.
Explanation:
Given;
6km due west, and
5km due north
The magnitude of her displacement is calculated by forming a right angled triangle. The hypotenuse side of the triangle is the girl's displacement.
d² = 5² + 6²
d² = 25 + 36
d² = 61
d = √61
d = 7.81 m
The direction of the girl is calculated as;
Therefore, the girl's displacement in both magnitude and direction is 7.81 m at 50.2⁰ North west.
Answer:
m = 8
Explanation:
A telescope is a device that allows us to see objects that were very far from us, it is built by the combination of two lenses, the one with the lowest focal length near the eye and that is the one or the one with the greatest focal length, the most eye-flounder . The magnification of the telescope is
m = - f₀ /
Where f₀ is the focal length of the lens and f_{e} is the false distance of the eyepiece.
It is this problem that gives us the diopter of each lens, these are related to the focal length in meters
D = 1 / f
Let's find the focal length
f₁ = 1 / D₁
f₁ = 1 / 1.16
f₁ = 0.862 m
f₂ = 1 / 9.37
f₂ = 0.1067 m
Therefore, the lens with f₂ is the eyepiece and the slow one with the
distance focal f₁ is the objective.
Let's calculate
m = - f₂ / f₁
m = - 0.862 / 0.1067
m = 8
Answer:
Solution:
As per the question:
Point charge, q =
Test charge,
Work done by the electric force,
Now,
We know that the electric potential at a point is given by:
where
r = separation distance between the charges.
Also,
The work done by the electric force i moving a test charge from point A to B in an electric field: