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Ulleksa [173]
4 years ago
7

 I NEED TO KNOW FAST PLZ SOMEONE KNOW THE ANSWER Spiral galaxies usually contain many young stars, so they often have a reddish

tint true or false
Physics
1 answer:
spayn [35]4 years ago
6 0
False. They often have a bluish tint.
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The impulse given to a ball with mass of 4 kg is 16 N s. If the ball starts from rest, what is its final velocity?
photoshop1234 [79]
The formula for impulse is F*(t₂-t₁)=m*(v₂-v₁), where F is the force, t is time, m is mass and v is velocity. 

In our case m*(v₂-v₁)=16 N s, m=4 kg, v₁=0 and t₁=0.

m*(v₂-0)=16 N s, we solve for v₂:

4*v₂= 16

v₂=16/4

v₂=4 m/s

So the final velocity of the ball is v₂=4 m/s.
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Electric current is a measure of
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Answer:

b. the amount of electric charge that passes within a certain amount of time

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A capacitor stores 5.6 x 10-7 C of charge when connected to a 6.0-V battery. How much charge does the capacitor store when conne
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3 years ago
Water in the oceans may become fresh water available to humans through the processes of
Darya [45]
<span>Water in the oceans may become fresh water available to humans through the processes of evaporation, condensation and precipitation.

In these processes, water is heated to a very high temperature until it evaporates in order to kill the germs and remove the salts which remains after water evaporation. The next step in condensing the water vapor (which is now fresh) and precipitating this vapor to be used by humans.</span>
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3 years ago
A 2kg hockey puck is sliding across the ice skating rink at 2 m/s. A player hits the puck so it's velocity increases to 10 m/s.
konstantin123 [22]

The work done on the puck is 96 J

Explanation:

According to the work-energy theorem, the work done on the hockey puck is equal to the change in kinetic energy of the puck.

Mathematically:

W=K_f -K_i= \frac{1}{2}mv^2-\frac{1}{2}mu^2

where

K_f = \frac{1}{2}mv^2 is the final kinetic energy of the puck, with

m = 2 kg being the mass of the puck

v = 10 m/s is the final speed

K_i = \frac{1}{2}mu^2 is the initial kinetic energy of the puck, with

u = 2 m/s being the initial speed of the puck

Substituting numbers into the equation, we find the work done by the player on the puck:

W=\frac{1}{2}(2)(10)^2 - \frac{1}{2}(2)(2)^2=96 J

Learn more about work and kinetic energy:

brainly.com/question/6763771  

brainly.com/question/6443626  

brainly.com/question/6536722

#LearnwithBrainly

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