ANY DENSE OBJECT
A mathematical equation for density is: Density = mass/volume or D = m/v. If something has a large mass compared to its volume, it has a high density. This is like a set of weights which can be small but heavy. But if an object has a small mass compared to its volume it has a lower density.
Pls give me a brainliest if this helps thx
Answer:
The coefficient of kinetic is
![u_{k}=0.59](https://tex.z-dn.net/?f=u_%7Bk%7D%3D0.59)
Explanation:
The forces in the axis 'x' and 'y' using law of Newton to find coefficient of kinetic friction
ΣF=m*a
ΣFy=W-N=0
ΣFy=Fn-Fu=m*a
![F_{u} =u_{k} *N\\F_{N}=25N\\N=W\\N=3.5kg*9.8\frac{m}{s^{2} }=34.3N](https://tex.z-dn.net/?f=F_%7Bu%7D%20%3Du_%7Bk%7D%20%2AN%5C%5CF_%7BN%7D%3D25N%5C%5CN%3DW%5C%5CN%3D3.5kg%2A9.8%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%20%7D%3D34.3N)
![F_{N}-F_{u}=m*a\\F_{N}-u_{k}*N=m*a\\u_{k}*N=F_{N}-m*a\\u_{k}=\frac{F_{N}-m*a}{N}](https://tex.z-dn.net/?f=F_%7BN%7D-F_%7Bu%7D%3Dm%2Aa%5C%5CF_%7BN%7D-u_%7Bk%7D%2AN%3Dm%2Aa%5C%5Cu_%7Bk%7D%2AN%3DF_%7BN%7D-m%2Aa%5C%5Cu_%7Bk%7D%3D%5Cfrac%7BF_%7BN%7D-m%2Aa%7D%7BN%7D)
Now to find the coefficient can find the acceleration using equation of uniform motion accelerated
![v_{f} ^{2}=v_{o}^{2}+2*a(x_{f}-x_{o})\\x_{o}=0\\v_{o}=0\\v_{f} ^{2}=2*a*x_{f}\\a=\frac{v_{f} ^{2}}{2*a*x_{f}}\\ a=\frac{(1.53\frac{m}{s} )^{2}}{2*0.91m}\\a= 1.28 \frac{m}{s^{2} }](https://tex.z-dn.net/?f=v_%7Bf%7D%20%5E%7B2%7D%3Dv_%7Bo%7D%5E%7B2%7D%2B2%2Aa%28x_%7Bf%7D-x_%7Bo%7D%29%5C%5Cx_%7Bo%7D%3D0%5C%5Cv_%7Bo%7D%3D0%5C%5Cv_%7Bf%7D%20%5E%7B2%7D%3D2%2Aa%2Ax_%7Bf%7D%5C%5Ca%3D%5Cfrac%7Bv_%7Bf%7D%20%5E%7B2%7D%7D%7B2%2Aa%2Ax_%7Bf%7D%7D%5C%5C%20a%3D%5Cfrac%7B%281.53%5Cfrac%7Bm%7D%7Bs%7D%20%29%5E%7B2%7D%7D%7B2%2A0.91m%7D%5C%5Ca%3D%201.28%20%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%20%7D)
So replacing the acceleration can fin the coefficient:
![u_{k}=\frac{F_{N}-m*a }{N}\\u_{k}=\frac{25N-(3.5kg*1.28\frac{m}{s^{2}} }{34.3N} \\u_{k}=0.59](https://tex.z-dn.net/?f=u_%7Bk%7D%3D%5Cfrac%7BF_%7BN%7D-m%2Aa%20%7D%7BN%7D%5C%5Cu_%7Bk%7D%3D%5Cfrac%7B25N-%283.5kg%2A1.28%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%7D%20%7D%7B34.3N%7D%20%5C%5Cu_%7Bk%7D%3D0.59)
Answer:
B
Explanation:
in a liquid the particles are widespread and move around each other but in a solid they move in place and are tightly packed
Answer:
6 gallons
Explanation:
At 30 mph, the fuel mileage is 25 mpg.
After 5 hours, the distance traveled is:
30 mi/hr × 5 hr = 150 mi
The amount of gas used is:
150 mi × (1 gal / 25 mi) = 6 gal