Ask question

Ask question

All categories

3 years ago

9

Birds cause a lot of damage to airplanes every year. To study this problem, the U.S Air force invented a chicken cannon. Air For

ce scientists use the cannon to shoot chicken bodies at airplanes in controlled tests. Then they analyze the damage the chicken bodies cause. Evaluate this model. in what way do you think it is helpful? What are some limitations?

2 answers:

Luba_88 [7]3 years ago

8 0

Answer:

to see how it affects the planes and to obsereve the damage the birds have taken

Explanation:

Gnesinka [82]3 years ago

6 0

Answer:

i have this qustion and i am in middle school you in

Explanation:

You might be interested in

Which two of the following involve the same energy transfer. Assume that the same substance and the same mass is involved in all

Elanso [62]

B. evaporation
c. condensation

They are opposite processes that involve the same transfer of energy

3 0

2 years ago

Calculate the magnitude of the electric field inside the solid at a distance of 9.50 cm from the center of the cavity. Express y

WITCHER [35]

Question:

A point charge of -2.14uC is located in the center of a spherical cavity of radius 6.55cm inside an insulating spherical charged solid. The charge density in the solid is 7.35×10−4 C/m^3.

a) Calculate the magnitude of the electric field inside the solid at a distance of 9.50cm from the center of the cavity.

Express your answer using two significant figures.

Answer:

The magnitude of the electric field inside the solid at a distance of 9.50cm from the center of the cavity $3.65\times 10^5N/C$

Explanation:

A point charge ,q = $-2.14\times 10^{-6} C$ is located in the center of a spherical cavity of radius , $r =6.55\times 10^{-2}$ m inside an insulating spherical charged solid.

The charge density in the solid , d = $7.35 \times 10^{-4}C/m^3.$

Distance from the center of the cavity,R = $9.5\times 10^{-2 }m$

Volume of shell of charge= V = $(\frac{4\pi}{3})[ R^3 - r^3 ]$

Charge on the shell ,Q = $V \times d'$

$Q =(\frac{4\pi}{3})[ R^3 - r^3 ] \times d$

$Q = 4.1888*\times 10^{-4 }[8.57375 - 2.81011 ]\times 7.35\times 10^{-4}$

$Q = 4.1888\times 10^{-4} [5.76364 ] \times 7.35 \times 10^{-4}$

$Q =2.4143 \times 10^{-4} \times 7.35 \times 10^ { -4}$

$Q =1.7745 \times 10^{-6 }C$

Electric field at $9.5\times 10^{-2}$ m due to shell $E1 = \frac{k Q}{R^2}$

E1 = $\frac{ 9 \times 10^9\times 1.7745\times 10^{-6 }}{ 90.25\times 10^{-4}}$

$E1 =1.769\times 10^6 N/C$

Electric field at $9.5\times 10^{-2}$ due to 'q' at center $E2 = \frac{kq}{R^2}$

E2 = $\frac{ - 9 \times 10^9\times 2.14\times 10^{-6 }}{ 90.25\times 10^{-4}}$

$E2 =2.134\times 10^6 N/C$

The magnitude of the electric field inside the solid at a distance of 9.50cm from the center of the cavity

= E2- E1

$=[ 2.134 - 1.769 ]\times 10^6$

$= 3.65\times 10^5 N/C$

8 0

3 years ago

A set of charged plates 0.00262 m apart has an electric field of 155 N/C between them. What is the potential difference between

mylen [45]

Answer: The potential difference between the plates = 0.4061V

Explanation:

Given that the

Electric field strength E = 155 N/C

Distance d = 0.00262 m

From the definition of electric field strength, is the ratio of potential difference V to the distance between the plates. That is

E = V/d

Substitute E and d into the above formula

155 = V/0.00262

Cross multiply

V = 155 × 0.00262

V = 0.4061 V

The potential difference between the plates is 0.4061 V

5 0

3 years ago

How many atoms of oxygen in the chemical formula 2 Ca(ClO2)2?

alexgriva [62]

Answer:

8

Explanation:

Ca(ClO2)2 - 2*2 = 4 Oxygen atoms

2 Ca(ClO2)2 - 2*4 = 8 Oxygen atoms

8 0

2 years ago

The phenomenon of water sticking to a surface, such as a window pane or

Korolek [52]

Answer:

Because of the Cohesion

4 0

1 year ago

Read 2 more answers