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matrenka [14]
3 years ago
9

A forklift raises a box weighing 475N from the floor to a height of 18m in 12 seconds. What power is produced by the forklift mo

tor in watts
Physics
1 answer:
Temka [501]3 years ago
6 0

The power produced is 712.5 W

Explanation:

First of all, we start by finding the work done by the forklift.

The work done on an object pushed in the same direction as the force is given by:

W=Fd

where

F is the magnitude of the force

d is the displacement of the object

In this problem,

F = 475 N is the force applied to raise the box

d = 18 m is the displacement

Substituting,

W=(475)(18)=8550 J

Now we can calculate the power, which is the ratio between the work done and the time taken:

P=\frac{W}{t}

Here we have,

W = 8550 J

t = 12 s

Substituting,

P=\frac{8550}{12}=712.5 W

Learn more about power here:

brainly.com/question/7956557

#LearnwithBrainly

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    In this reaction we have:

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on the reactant side:

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            1 mole of oxygen gas:   2 atoms of O

                             total atoms:    4 atoms

According to the law of conservation of matter "in a chemical reaction, matter is neither created nor destroyed".

We expect to find 4 atoms of products which is MgO on the product side.

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A pitcher throws a 0.140 kg baseball, and it approaches the bat at a speed of 35.0 m/s. The bat does Wnc = 75.0 J of work on the
Eva8 [605]

Answer:

The speed of the ball is 42.5 m/s

Explanation:

The initial kinetic energy of the ball is:

K_1=\frac{1}{2} m v_0^2=\frac{1}{2}*0.140 kg*(35.0 m/s)^2= 85.75 J

The speed of the ball after leaving the bat is:

K_2=K_1+W_{nc}\\ \frac{1}{2}mV^2= 85.75 J + 75 J\\ (\frac{1}{2}mV^2)2=( 160.75 J)2\\ mV^2= 321.5 J\\ V^2= \frac{321.5 J}{0.140kg} \\ V=\sqrt{\frac{321.5 J}{0.140kg}}

V=47.92 m/s

Using kinematic equation we can find the speed of the ball after being 25 m above the point of collision:

V_f^2-V^2=-2gh

V_f^2-(47.92 m/s)^2=-2*9.81m/s^2*25m

V_f^2=-2*9.81m/s^2*25m+(47.92 m/s)^2

V_f=\sqrt{-2*9.81m/s^2*25m+(47.92 m/s)^2}

V_f=42.5m/s

3 0
2 years ago
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