The distance travelled during the given time can be found out by using the equations of motion.
The distance traveled during the time interval is "13810.8 m".
First, we will find the deceleration of the motorcycle by using the first <em>equation of motion</em>:
where,
vi = initial velocity = (518 km/h)
= 143.89 m/s
vf = final veocity = 60 % of 143.89 m/s = (0.6)(143.89 m/s) = 86.33 m/s
a = deceleration = ?
t =time interval = 2 min = 120 s
Therefore,
a = -0.48 m/s²
Now, we will use the second <em>equation of motion </em>to find out the distance traveled (s):
<u>s = 13810.8 m = 13.81 km</u>
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Learn more about the equations of motion here:
brainly.com/question/20594939?referrer=searchResults
The attached picture shows the equations of motion.
The answer is 0.981 J
E = m · g · h<span>
E - energy
m - mass
g - gravitational acceleration
h - height
We know:
E = ?
m = 0.10 kg
g = 9.81 m/s</span>²
h = 1 m
E = 0.10 kg * 9.81 m/s² * 1 m = 0.981 J
Explanation:
Given that,
Displacement in ice block, 
Force exerted by water, 
To find,
Work done by the force during the displacement.
Solve,
We know that the product of force and displacement is called work done. It is also equal to the dot product of force and displacement as :
We know that, i.i = j.j = k.k = 1
So, the work done by the force on the block during the displacement is 4181 Joules.
<u>Answer</u>
8. 2 Hz
9. 0.5 seconds
10. 20 cm
<u>Explanation</u>
<u>Q 8</u>
Frequency is the number of oscillation in a unit time. It is the rate at which something repeats itself in a second.
In this case, the spring bob up and down 2 times per second.
∴ Frequency = 2 Hz
<u>Q 9</u>
Period is the time taken to complete one oscillation.
2 oscillations takes 1 second
1 oscillation = 1/2 seconds.
∴ Period = 0.5 seconds
<u>Q 10</u>
Amplitude is the the maximum displacement of the spring.
In this case the spring bob up 20 cm. This is it's displacement.
∴ Amplitude = 20 cm
Wow ! This is not simple. At first, it looks like there's not enough information, because we don't know the mass of the cars. But I"m pretty sure it turns out that we don't need to know it.
At the top of the first hill, the car's potential energy is
PE = (mass) x (gravity) x (height) .
At the bottom, the car's kinetic energy is
KE = (1/2) (mass) (speed²) .
You said that the car's speed is 70 m/s at the bottom of the hill,
and you also said that 10% of the energy will be lost on the way
down. So now, here comes the big jump. Put a comment under
my answer if you don't see where I got this equation:
KE = 0.9 PE
(1/2) (mass) (70 m/s)² = (0.9) (mass) (gravity) (height)
Divide each side by (mass):
(0.5) (4900 m²/s²) = (0.9) (9.8 m/s²) (height)
(There goes the mass. As long as the whole thing is 90% efficient,
the solution will be the same for any number of cars, loaded with
any number of passengers.)
Divide each side by (0.9):
(0.5/0.9) (4900 m²/s²) = (9.8 m/s²) (height)
Divide each side by (9.8 m/s²):
Height = (5/9)(4900 m²/s²) / (9.8 m/s²)
= (5 x 4900 m²/s²) / (9 x 9.8 m/s²)
= (24,500 / 88.2) (m²/s²) / (m/s²)
= 277-7/9 meters
(about 911 feet)
