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3 years ago

The temperature on the moon is

2 answers:

7 0

When the sun shines, it illuminates only one part of the moon. The article states, "<span>Daytime on one side of the moon lasts about 13 and a half days, followed by 13 and a half nights of darkness. When sunlight hits the moon's surface, the temperature can reach 253 degrees F (123 C). The "dark side of the moon" can have temperatures dipping to minus 243 F (minus 153 C).</span><span>Oct 22, 2012". Therefore, b is correct</span>

Nuetrik [128]3 years ago

4 0

B.

It can go from very hot to very cold, it depends on the area of the moon and where the sunlight hits.

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Definition of distance travelled?

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Answer:

distance traveled is a total length of the path traveled between two positions.

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Consider a box sitting in the back of a pickup. The pickup accelerates to the right, and because the bed of the pickup is sticky

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The most common form of angina is _______ angina. A. microvascular B. variant C. stable D. unstable

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The most common form of angina is stable angina.

C. stable

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An atom emits a photon when one of its electrons:

disa [49]

Answer:

undergoes a transition to a quantum state of lower energy

Explanation:

When electrons in an atom move to another quantum state, they emit/absorb a photon according to the following:

- If the electron is moving to a higher energy state, it absorbs a photon (because it needs energy to move to a higher energy level, so it must absorb the energy of the photon)

- if the electron is moving to a lower energy state, it emits a photon (because it releases the excess energy)

In particular, the energy of the absorbed/emitted photon is exactly equal to the difference in energy between the two levels of the electron transition:

$E=|E_1 - E_2|$

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3 years ago

Show which of the following functional forms work or do not work as solutions to this differential equation (known as 'the wave

Akimi4 [234]

Answer:

E = A cos (Bx + Ct) and E = A cos (Bx + Ct + D)

Explanation:

The wave equation is

d²y / dx² = 1 /v² d²y / dt²

Where v is the speed of the wave

Let's review the solutions

In this case y = E

a) E = A sin Bt

This cannot be a solution because the part in x is missing

dE / dx = 0

b) E = A cos (Bt + c)

There is no solution missing the Part in x

dE / dx = 0

c) E = A x² t²

The parts are fine, but this solution is not an oscillating wave, so it is not an acceptable solution of the wave equation

d) E = A cos (Bx + Ct) and E = A cos (Bx + Ct + D)

Both are very similar

Let's make the derivatives

dE / dx = -A B sin (Bx + Ct + D)

d²E / dx² = -A B² cos (Bx + Ct + D)

dE / dt = - A C sin (Bx + Ct + D)

d²E / dt² = -A C² cos (Bx + Ct + D)

We substitute in the wave equation

-A B² cos (Bx + Ct + D) = 1 / v² (-A C² cos (Bx + Ct + D))

B² = 1 / v² (C²)

v² = (C / B)²

v = C / B

We see that the two equations can be a solution to the wave equation, the last one is the slightly more general solution

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3 years ago