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bazaltina [42]
3 years ago
14

A pot of water is heated over a fire, and then frozen peas are added to the hot water. What happens to the energy in this situat

ion?
Chemistry
2 answers:
ZanzabumX [31]3 years ago
7 0

Answer:

Energy will enter the peas from the water

Explanation:

An exothermic process would occur as the energy gathered by the heated water is transferred to the peas.

AnnZ [28]3 years ago
4 0

Explanation:

It is known that transfer of energy always occur from hot substance to cool substance.

Therefore, when frozen peas are added to heated water then potential energy of peas will start to convert into kinetic energy as transfer of energy will take place from water to peas.

This is because water molecules will collide with molecules of peas. Hence, peas will also gain energy.

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Please begging you guys someone help me
BaLLatris [955]

Answer:

See Explanation

Explanation:

10) From the options provided for this question, gamma particle is the most energetic. Recall that gamma rays are high energy electromagnetic radiation which are capable of causing a high degree of ionization in matter.

11) The bombardment of U-235 with neutrons leads to the reaction;

U\frac{235}{92}  + n\frac{1}{0}---> I\frac{138}{53}  + Y\frac{95}{39} +3n \frac{1}{0}

Hence

a = 92, b= 95, c= 53

12) In positron emission, a proton is transformed into a neutron. The mass number of the daughter nucleus is the same as its parent but the atomic number decreases by 1.

Hence;

Th\frac{231}{90} -----> e\frac{1}{0} +Ac \frac{231}{89}

4 0
3 years ago
Determine the distance of closest approach (in fm) before the alpha particle reverses direction. Assume the lead nucleus remains
kiruha [24]

Answer:

Take E(alpha particle energy) = 5.5 MeV (5.5x106x1.6x10-19)

If the charge on the lead nucleus is +82e(atomic number of lead is 82) = +82x1.6x10-19 C and the charge on the alpha particle is +2e = 2x1.6x10-19 C

Using dc = (1/4πεo)qQ/Eα we have

dc = [9x10^9x(2x1.6x10-19x82x1.6x10-19)]/5.5x10-13 = 6.67x10^-13m. = 6.67 x 10^-13 x 10^15 = 6.67 x 10^2fm

Note: 1meter = 10^15fentometer

Explanation:

This is well inside the atom but some eight nuclear diameters from the centre of the lead nucleus.

7 0
3 years ago
Write the name of the alkyne next to the drawing of the molecule. (2 points)
azamat

1) 1-Pentyne

2) But-2-yne

3) Ethyne

4) 1-Propyne

5) 1-Butyne

6) Pent-2-yne

<h3>What is alkyne?</h3>

Molecules that contain a triple bond between two carbon atoms are known as alkynes.

1) The number of carbon on the longest chain = 5, (two carbon atoms between the triple bond) therefore the prefix is pen-

The functional group is the triple bond on the first carbon with the suffix -yne

The name of the compound is 1-Pentyne

2) There are 4 carbon atoms on the longest chain, therefore, the prefix is but-

The location of the triple bond functional group (suffix; -yne) is on the second carbon atom

Therefore, the name of the compound is But-2-yne

3) The triple bond functional group is between the only two carbon atoms, therefore, the name is Ethyne

4) The number of carbon atoms = 3, with a prefix prop-, and the functional group on the first carbon atom on the longest chain is the triple bond, with suffix -yne

Therefore, the name of the compound is 1-Propyne

5) The number of carbon atoms on the longest chain = 4, the prefix is but-

The location of the triple bond functional group (suffix -yne) is on the first carbon atom

Therefore, the name is 1-Butyne

6) The number of carbon atoms on the longest chain = 5, the prefix of the compound is pen-

The location of the triple bond functional group (suffix; -yne) is on the second carbon atom, therefore;

The name of the compound is Pent-2-yne

Learn more about alkyne here:

brainly.com/question/23508203

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6 0
2 years ago
Two methods can be used to determine the rate law for a reaction. One is a graphical method used to determine the integrated rat
zloy xaker [14]

Answer:

Initial rate method

Explanation:

The initial rate of the reaction is dictated by the different concentrations of one reactant, while other reactants remain constant.

7 0
3 years ago
List and explain the four most important factors that control the relative reactivity of a carbonyl-containing functional group
ioda

Resonance, leaving group, carbonyl carbon delta+, and steric effect is the most crucial variables that affect the relative reactivity of a functional group containing a carbonyl in an addition or substitution process.

Discussion:

1. Carbonyl Carbon Delta+: The carbonyl group becomes more electrophilic and accelerates nucleophilic assault when the carbonyl carbon delta+ is bigger.

2. Resonance: When the carbonyl is transformed into the tetrahedral adduct, it may be lost. Loss of resonance increases the energy of the transition state for this nucleophilic assault because resonance has the function of stabilizing. Therefore, a carbonyl functional group's resistance to nucleophilic attack increases as resonance in the group increases in importance.

3. Leaving group: Tetrahedral adduct fragmentation is encouraged by a better LG.

4. Steric effects: The nucleophilic attack on carbonyl carbon is delayed when sterically impeded.

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8 0
1 year ago
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