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Zepler [3.9K]
3 years ago
12

Bob is studying waves in science and learns that the energy of a wave is directly proportional to the square of the waves amplit

ude. If the amplitude of a wave changes from 2m to 1m, what should he predict as the effect on energy of the wave? A) The energy is halved. B) The energy is doubled. C) The energy is quartered. D) The energy is quadrupled.
Physics
2 answers:
alex41 [277]3 years ago
8 0

Answer:

It's C

Explanation:

Since E ∝ amplitude2 then as the amplitude is halved the energy is quartered.

Plugging in to check

amplitude2=E

22=4

12=1

Mrrafil [7]3 years ago
6 0
For a simple harmonic motion energy is given with:
E=\frac{1}{2}kA^2
Where k is a constant that depends on the type of the wave you are looking at and A is amplitude.
Let's calculate the energy of the wave using two different amplitudes given in the problem:
E_1=\frac{1}{2}k(1)^2=\frac{1}{2}k\\E_2=\frac{1}{2}k(2)^2=\frac{4}{2}k=2k\\
We can see that energy associated with the wave is 4 times smaller when we decrease its amplitude by half. So the answer should be C.


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Answer:

Explanation:

Given that,

Mass per unit length is

μ = 4.87g/cm

μ=4.87g/cm × 1kg/1000g × 100cm/m

μ = 0.487kg/m

Tension

τ = 16.7N

Amplitude

A = 0.101mm

Frequency

f = 71 Hz

The wave is traveling in the negative direction

Given the wave form

y(x,t) = ym• Sin(kx + ωt)

A. Find ym?

ym is the amplitude of the waveform and it is given as

ym = A = 0.101mm

ym = 0.101mm

B. Find k?

k is the wavenumber and it can be determined using

k = 2π / λ

Then, we need to calculate the wavelength λ using

V = fλ

Then, λ = V/f

We have the frequency but we don't have the velocity, then we need to calculate the velocity using

v = √(τ/μ)

v = √(16.7/0.487)

v = 34.29

v = 5.86 m/s

Then, we can know the wavelength

λ = V/f = 5.86 / 71

λ = 0.0825 m

So, we can know the wavenumber

k = 2π/λ

k = 2π / 0.0825

k = 76.18 rad/m

C. Find ω?

This is the angular frequency and it can be determined using

ω = 2πf

ω = 2π × 71

ω = +446.11 rad/s

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5 0
3 years ago
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qwelly [4]

Answer:

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We know that

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Step 2:

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Hence, the train takes 66.28 s to come to stop from velocity 41.425m/s.

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