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Zepler [3.9K]
3 years ago
12

Bob is studying waves in science and learns that the energy of a wave is directly proportional to the square of the waves amplit

ude. If the amplitude of a wave changes from 2m to 1m, what should he predict as the effect on energy of the wave? A) The energy is halved. B) The energy is doubled. C) The energy is quartered. D) The energy is quadrupled.
Physics
2 answers:
alex41 [277]3 years ago
8 0

Answer:

It's C

Explanation:

Since E ∝ amplitude2 then as the amplitude is halved the energy is quartered.

Plugging in to check

amplitude2=E

22=4

12=1

Mrrafil [7]3 years ago
6 0
For a simple harmonic motion energy is given with:
E=\frac{1}{2}kA^2
Where k is a constant that depends on the type of the wave you are looking at and A is amplitude.
Let's calculate the energy of the wave using two different amplitudes given in the problem:
E_1=\frac{1}{2}k(1)^2=\frac{1}{2}k\\E_2=\frac{1}{2}k(2)^2=\frac{4}{2}k=2k\\
We can see that energy associated with the wave is 4 times smaller when we decrease its amplitude by half. So the answer should be C.


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3 0
3 years ago
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Vika [28.1K]
A=Fh
A - work
F - force
h - distance

F=mg
m - mass (god+basket)

so
A=mgh
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6 0
3 years ago
Two technicians are discussing U-joints. Technician A says that a defective U-joint could cause a loud clunk when the transmissi
Nookie1986 [14]

Answer:

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6 0
3 years ago
If 250 g of calcium chlorate decomposes into calcium chloride and oxygen, what mass of oxygen would be produced?
sineoko [7]

115.94g of O₂ are produced by 250g of Ca(ClO₃)₂

<u>Explanation:</u>

Ca(ClO₃)₂ -->CaCl₂ + 3O₂

One mole of calcium chlorate give three moles of oxygen.

Molar mass of calcium chlorate is

40+(35.5+16*3)*2 = 207g/mol

Molar mass of Oxygen = 32g

1 mole of calcium chlorate decomposes to form 3 moles of oxygen.

So,

207g of Ca(ClO₃)₂ produces 3 X 32g of O₂

250g of Ca(ClO₃)₂ will produce = \frac{3 X 32}{207} X 250

                                                    = 115.94g of O₂

Therefore, 115.94g of O₂ are produced by 250g of Ca(ClO₃)₂

7 0
3 years ago
THE LENGTH OF A PENDULUM IS (1.5±0.01)m AND THE ACCELERATION DUE TO GRAVITY IS TAKEN AS (9.8±0.1)ms-² calculate the time period
tiny-mole [99]

Answer:

  2.4583 ± 0.0207 seconds

Explanation:

The time period of a pendulum is approximately given by the formula ...

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The maximum period will be achieved when length is longest and gravity is smallest:

  Tmax = 2π√(1.51/9.7) ≈ 2.47903 . . . seconds

The minimum period will be achieved for the opposite conditions: minimum length and maximum gravity:

  Tmin = 2π√(1.49/9.9) ≈ 2.43756 . . . seconds

If we want to express the uncertainty using a symmetrical range, we need to find half their sum and half their difference.

  T = (2.47903 +2.43756)/2 ± (2.47903 -2.43756)/2

  T ≈ 2.4583 ± 0.0207 . . . seconds

__

We have about 2+ significant digits in the given parameters, so the time might be rounded to 2.46±0.02 seconds.

5 0
3 years ago
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