Answer:
D
Explanation:
The answer is Niels Bohr's planetary model, the difference between this model and all of the other models is that the Bohr's PM Is more of layers of
Nucleus - Protons and Neutrons
Electron Orbital - Period 1 Elements
2 electrons
Electron Orbital - Period 2 Elements
8 electrons
Electron Orbital - Period 3 Elements
8 electrons
If that made sense-
A=Fh
A - work
F - force
h - distance
F=mg
m - mass (god+basket)
so
A=mgh
187 = m*10*4
187=40m
m=187/40
m=4.675 kg
or 4kg and 675g
pretty small dog...
Answer:
Technician A and Technician B are correct.
Explanation:
115.94g of O₂ are produced by 250g of Ca(ClO₃)₂
<u>Explanation:</u>
Ca(ClO₃)₂ -->CaCl₂ + 3O₂
One mole of calcium chlorate give three moles of oxygen.
Molar mass of calcium chlorate is
40+(35.5+16*3)*2 = 207g/mol
Molar mass of Oxygen = 32g
1 mole of calcium chlorate decomposes to form 3 moles of oxygen.
So,
207g of Ca(ClO₃)₂ produces 3 X 32g of O₂
250g of Ca(ClO₃)₂ will produce = 
= 115.94g of O₂
Therefore, 115.94g of O₂ are produced by 250g of Ca(ClO₃)₂
Answer:
2.4583 ± 0.0207 seconds
Explanation:
The time period of a pendulum is approximately given by the formula ...
T = 2π√(L/g)
The maximum period will be achieved when length is longest and gravity is smallest:
Tmax = 2π√(1.51/9.7) ≈ 2.47903 . . . seconds
The minimum period will be achieved for the opposite conditions: minimum length and maximum gravity:
Tmin = 2π√(1.49/9.9) ≈ 2.43756 . . . seconds
If we want to express the uncertainty using a symmetrical range, we need to find half their sum and half their difference.
T = (2.47903 +2.43756)/2 ± (2.47903 -2.43756)/2
T ≈ 2.4583 ± 0.0207 . . . seconds
__
We have about 2+ significant digits in the given parameters, so the time might be rounded to 2.46±0.02 seconds.