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Travka [436]
3 years ago
15

How does the radioactive isotope C-14 differ from its stable counterpart C-12?

Chemistry
2 answers:
ahrayia [7]3 years ago
7 0
C-14 has 2 more neutrons than C-12

C-14
6 protons
8 neutrons

C-12
6 protons
6 neutrons
otez555 [7]3 years ago
4 0

Isotope  is defined as atom of same element with same atomic number but different mass number.

Here, atomic number for C-14 and C-12  is 6 but mass number is 14 and 12 respectively.

Atomic number is equal to number of protons and electrons in an atom and mass number is equal to sum of number of protons and neutrons in nucleus of an atom.

A=n_{p}+n_{n}

Since, both have same atomic number, the number of protons will be 6 for both but they have different number of neutrons.

Number of neutrons in C-12:

n_{n}=12-n_{p}=12-6=6

Number of neutrons in C-14:

n_{n}=14-n_{p}=14-6=8

The number of neutrons in C-12 is 6 and that in C-14 is 8. Therefore, isotope C-14 differ from the stable C-12 in number of neutrons.

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If an atom has 13 electrons how many electron shells does it have
svlad2 [7]

Answer:

Explanation:

If an atom has 13 electrons then it belongs to p-block of periodic table.

s level can accommodate 2 electrons.

p level can accommodate 6 electrons.

13 means 1s2 2s2 2p6 3s2 3p1.

As you can see there totally 5 sub-shells.

Total number of shells are 3(1,2,3).

4 0
3 years ago
Someone please help me
ehidna [41]
I hop this will help u

8 0
3 years ago
A laboratory analysis of a sample finds it is composed of 38.8% carbon, 16.2% hydrogen, and 45.1% nitrogen. What is its empirica
Sladkaya [172]

Answer: The empirical formula for the given compound is CH_5N

Explanation : Given,

Percentage of C = 38.8 %

Percentage of H = 16.2 %

Percentage of N = 45.1 %

Let the mass of compound be 100 g. So, percentages given are taken as mass.

Mass of C = 38.8 g

Mass of H = 16.2 g

Mass of N = 45.4 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{38.8g}{12g/mole}=3.23moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{16.2g}{1g/mole}=16.2moles

Moles of Nitrogen = \frac{\text{Given mass of nitrogen}}{\text{Molar mass of nitrogen}}=\frac{45.4g}{14g/mole}=3.24moles

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 3.23 moles.

For Carbon = \frac{3.23}{3.23}=1

For Hydrogen  = \frac{16.2}{3.23}=5.01\approx 5

For Oxygen  = \frac{3.24}{3.23}=1.00\approx 1

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : N = 1 : 5 : 1

Hence, the empirical formula for the given compound is C_1H_5N_1=CH_5N

3 0
3 years ago
A chemistry student needs 60.0 g of tetrahydrofuran for an experiment. By consulting the CRC Handbook of Chemistry and Physics,
Evgen [1.6K]

Answer:

67.492cm^3

Explanation:

To get the volume of tetrahydrofuran needed, what the student need to do is to apply mathematical calculations.

We know quite well that to obtain the volume of a substance, given the mass of the substance and the density of the substance is possible.

The volume of the substance is simply the mass of the substance divided by the density of the substance.

This is thus volume = mass/density

The mass given is the question is 60g while the density given is 0.889g/cm^3

The volume = 60/0.889 = 67.492cm^3

8 0
3 years ago
What are the main components in dna
krek1111 [17]
Adenine , guanine, cytosine and thymine
8 0
2 years ago
Read 2 more answers
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