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fredd [130]
3 years ago
6

A chemistry student needs 60.0 g of tetrahydrofuran for an experiment. By consulting the CRC Handbook of Chemistry and Physics,

the student discovers that the density of tetrahydrofuran is 0.889g*cm^-3 . Calculate the volume of tetrahydrofuran the student should pour out.
Be sure your answer has the correct number of significant digits.
Chemistry
1 answer:
Evgen [1.6K]3 years ago
8 0

Answer:

67.492cm^3

Explanation:

To get the volume of tetrahydrofuran needed, what the student need to do is to apply mathematical calculations.

We know quite well that to obtain the volume of a substance, given the mass of the substance and the density of the substance is possible.

The volume of the substance is simply the mass of the substance divided by the density of the substance.

This is thus volume = mass/density

The mass given is the question is 60g while the density given is 0.889g/cm^3

The volume = 60/0.889 = 67.492cm^3

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What is the possible or stored energy in an object called?
DIA [1.3K]

Answer:

Potential energy is the energy stored within an object, due to the object's position, arrangement or state. Potential energy is one of the two main forms of energy, along with kinetic energy.

Explanation:

4 0
3 years ago
Given 6.23 mol Al find the atoms of Al
swat32

Answer:

The answer is

<h3>3.75 × 10²⁴ atoms of Al</h3>

Explanation:

To find the number of atoms of Al given it's number of moles we use the formula

<h3>N = n × L</h3>

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question

n = 6.23 mol

We have

N = 6.23 × 6.02 × 10²³

We have the final answer as

<h3>3.75 × 10²⁴ atoms of Al</h3>

Hope this helps you

3 0
3 years ago
PLEASE HELP ASAP!!!!
il63 [147K]
Oh that’s 10 I believe
8 0
3 years ago
A solution containing CaCl2 is mixed with a solution of Li2C2O4 to form a solution that is 3.5 × 10-4 M in calcium ion and 2.33
natka813 [3]

This is an incomplete question, here is a complete question.

A solution containing CaCl₂ is mixed with a solution of Li₂C₂O₄ to form a solution that is 3.5 × 10⁻⁴ M in calcium ion and 2.33 × 10⁻⁴ M in oxalate ion. What will happen once these solutions are mixed? Ksp (CaC₂O₄) = 2.3 × 10⁻⁹

A. Nothing will happen since both calcium chloride and lithium oxalate are soluble compounds.

B. Nothing will happen Ksp > Q for all possible precipitants.

C. A precipitate will form as calcium oxalate is not soluble to any extent.

D. A precipitate will form since Q > Ksp for calcium oxalate.

Answer : The correct option is, (D) A precipitate will form since Q > Ksp for calcium oxalate.

Explanation :

Concentration of Ca^{2+} = 3.5\times 10^{-4}M

Concentration of C_2O_4^{2-} = 2.33\times 10^{-4}M

The equilibrium chemical reaction will be:

CaC_2O_4\rightleftharpoons Ca^{2+}+C_2O_4^{2-}

The solubility constant expression for this reaction is:

K_{sp}=[Ca^{2+}][C_2O_4^{2-}]=2.3\times 10^{-9}

Now we have to calculate the ionic product for calcium oxalate.

Q_{sp}=[Ca^{2+}][C_2O_4^{2-}]

Q_{sp}=(3.5\times 10^{-4})\times (2.33\times 10^{-4)

Q_{sp}=8.2\times 10^{-8}

From this we conclude that, Q_{sp}>K_{sp} that means a white solid precipitate of calcium oxalate will be formed when the solutions are mixed.

Hence, the correct option is, (D)

4 0
3 years ago
Today is October 31 and we view or third quarter on what date did we reserve the last new moon
Mrrafil [7]
Answer: March 21

Explanation: March 21
6 0
3 years ago
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