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bekas [8.4K]
3 years ago
13

A laboratory analysis of a sample finds it is composed of 38.8% carbon, 16.2% hydrogen, and 45.1% nitrogen. What is its empirica

l formula? Give your answer in the form C#H#N#, where the number following the element’s symbol corresponds to the subscript in the formula.
Chemistry
1 answer:
Sladkaya [172]3 years ago
3 0

Answer: The empirical formula for the given compound is CH_5N

Explanation : Given,

Percentage of C = 38.8 %

Percentage of H = 16.2 %

Percentage of N = 45.1 %

Let the mass of compound be 100 g. So, percentages given are taken as mass.

Mass of C = 38.8 g

Mass of H = 16.2 g

Mass of N = 45.4 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{38.8g}{12g/mole}=3.23moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{16.2g}{1g/mole}=16.2moles

Moles of Nitrogen = \frac{\text{Given mass of nitrogen}}{\text{Molar mass of nitrogen}}=\frac{45.4g}{14g/mole}=3.24moles

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 3.23 moles.

For Carbon = \frac{3.23}{3.23}=1

For Hydrogen  = \frac{16.2}{3.23}=5.01\approx 5

For Oxygen  = \frac{3.24}{3.23}=1.00\approx 1

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : N = 1 : 5 : 1

Hence, the empirical formula for the given compound is C_1H_5N_1=CH_5N

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Please help me with chemistry
vodka [1.7K]

Table Giving Answer

Element Atomic mass % Amount

Mg_24     24                79    18.96

Mg_25 25                10    2.5

Mg_26 26                11   2.86

   

Total                     24.32

Discussion

The method of calculation for this table, which was done in Excel (a spread sheet) is shown below. Assume that there is 100 grams of material of "pure" magnesium. What is it's mass?

<em><u>Sample  Calculation</u></em>

The the sample atomic mass = 24

Mass = % * sample atomic mass

Mass = 79% * 24

Mass = (79/100) * 24

Mass = 18.96

<em><u>Note</u></em>

The other two elements are found exactly the same as the sample calculation.

Then all you do is add the 3 masses together.

Answer

The mass of Mg to 1 decimal place is 24.3 <<<< Answer.


7 0
3 years ago
How many moles of HCl are in 30.00mL of a 0.1000M HCl solution? A. 0.003000mol. B. 300.0mol C. 0.03000mol D. 3.000mol
Katyanochek1 [597]

Given the volume of HCl solution = 30.00 mL

Molarity of HCl solution = 0.1000 M

Molarity, moles and volume are related by the equation:

Molarity = \frac{Moles of solute}{Volume of solution (L)}

Converting volume of HCl from mL to L:

30.00 mL * \frac{1 L}{1000mL}=0.030000 L

Calculating moles of HCl from volume in L and molarity:

0.03000 L * \frac{0.1000mol}{L}= 0.003000 mol HCl

The final moles would be reported to 4 sig figs. So the correct answer will be 0.03000 mol HCl

Correct option: C. 0.03000mol

7 0
3 years ago
2. An element is all the way through,​
elena55 [62]
?? Is that the whole question?
6 0
3 years ago
Help me on question 5 pls
Gre4nikov [31]
Ca +2
At -1
In +3
Sr +2
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Fr +1
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7 0
3 years ago
Which of the following is the number of moles of solute that is dissolved in 1 liter of solution?
Komok [63]
I believe the correct answer is option B. Molarity is the <span>number of moles of solute that is dissolved in 1 liter of solution. It is another way of expressing concentration of a mixture especially for solutions. Percent by mass is grams solute per grams of solution. Percent by volume is liter solute per liter per solution.</span>
4 0
3 years ago
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