Their linear inertia is equivalent to their masses. Let the inertia of the first moose be m₁ and the second be m₂.
m₁u + m₂u = (m₁ + m₂) x 1/3 u
3m₁ + 3m₂ = m₁ + m₂
3 m₁/m₂ + 3 = m₁/m₂ + 1
m₁/m₂ = 2
The ratio of their inertias is 2
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The Correct Answer would 100% be:
Option "C".
"People in location C would complain about foul taste in water".
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48 meters.
12 m/s and 4 seconds, so 4*12=48.

Explanation:
Given:


The cross product
is given by


