Answer:
(a) = 0 N
(b) = 2.4 N
Explanation:
given
box of banana weight = 40.0 N
coefficient of static friction μ = 0.40
coefficient of kinetic friction = 0.20
a). when no horizontal force is applied .
according to Newton 's third law of motion If there is no force applied to the box,so the frictional force exerted is 0 N
b) magnitude of friction force
box and the box is initially at rest
friction force =.Static friction coefficient × weight of the box
friction force = 0.40 × 6
friction force = 2.4 N
Answer:
Explanation:
The package had the same velocity as the plane when it was dropped. Newton's 1st Law says that "an object in motion tends to stay in motion, at the same velocity, in a straight line unless acted on by an outside force".
There only outside force acting on the package was its weight -- that force is straight down. The horizontal velocity that the plane gave the package continued (as Newton said it would), so as it fell, horizontally it kept pace with the plane.
Assuming no other forces are acting on the wheelbarrow, it must be stationary.
Answer:
Because when people under the age of 21 try to buy alcohol, they need to be verified by their state that they are that age. So if they are under legal age, 21, the store isn't allowed to give them the Alcoholic beverage.
Explanation:
The spring constant is 147 N/m
Given the mass of the block is 2.00 kg , the mass of the body is 300 g and the length of the spring is 2.00 cm
We need to find the spring constant
A spring is an object that can be deformed by a force and then return to its original shape after the force is removed.
The force required to stretch an elastic object such as a metal spring is directly proportional to the extension of the spring
We know that F = kx
300(9.8)= k (0.02)
k = 147.15 N/m
Rounding off to the nearest is 147N/m
The spring constant is 147N/m
Learn more about Hooke's law here
brainly.com/question/15365772
#SPJ4
