Explanation:
The area between the speed-time graph f a body and time axis measures the distance travelled by the body
We are given the equation:
<span>x = 11t^2
</span>
We use that equation to calculate for the distance traveled.
For (a)
At t=2.20 sec,
x =53.24 meters
At t=2.95 sec,
x =95.73 meters
Velocity = (95.73 meters - 53.24<span> meters) / (2.95 s - 2.20 s ) = 56.65 m/s
</span>For (b)
At t=2.20 sec,
x =53.24 meters
At t=2.40 sec,
x =63.36 meters
Velocity = (63.36 meters - 53.24<span> meters) / (2.40 s - 2.20 s ) = 50.6 m/s</span>
The Pacific plate collides with and is subducted under four other crustal plates. The area where this happens has lots of volcanic activity. This area is called the Ring of Fire.
This is a place under the Pacific Ocean and it has numerous
volcanic eruptions and earthquakes and so this region is called the Ring of
Fire. In this place there are about 450 active and dormant volcanoes and it is
almost 75 percent of the volcanoes present in our earth.
Answer:height above ground at which projectile have velocity
0.5v is (0.0375v^2)
Explanation:
Using Vf = Vi - gt
Where Vf is final velocity
Vi is initial velocity
g is the acceleration due to gravity
t is the time taken
So, 0.5v = v - gt
t = 0.05v
Therefore height h = vt - 0.5gt^2
Subtitute t
h = 0.05v^2 - 0.0125v^2
h = 0.0375v^2
