C)Weight
A)An attraction between two objects that have mass
B)Force decreases as distance increases.
grav force of massive planet increases your weight
Answer: Both cannonballs will hit the ground at the same time.
Explanation:
Suppose that a given object is on the air. The only force acting on the object (if we ignore air friction and such) will be the gravitational force.
then the acceleration equation is only on the vertical axis, and can be written as:
a(t) = -(9.8 m/s^2)
Now, to get the vertical velocity equation, we need to integrate over time.
v(t) = -(9.8 m/s^2)*t + v0
Where v0 is the initial velocity of the object in the vertical axis.
if the object is dropped (or it only has initial velocity on the horizontal axis) then v0 = 0m/s
and:
v(t) = -(9.8 m/s^2)*t
Now, if two objects are initially at the same height (both cannonballs start 1 m above the ground)
And both objects have the same vertical velocity, we can conclude that both objects will hit the ground at the same time.
You can notice that the fact that one ball is fired horizontally and the other is only dropped does not affect this, because we only analyze the vertical problem, not the horizontal one. (This is something useful to remember, we can separate the vertical and horizontal movement in these type of problems)
Answer:
(i) Relative velocity of B w.r.t A= Sum of speeds of trains
=54+90
=144kmph
(ii)Relative velocity of B w.r.t Ground(G)=v
B/G
=−90kmph
v
G
=0
Relative velocity of ground(G) w.r.t B =v
G/B
=v
G
−v
B/G
v
G/B
=0−(−90)
v
G/B
=90kmph
Answer:
0 J
Explanation:
The weightlifter will have performed some work raising the mass to its current height, he is performing no work at all while holding it there.
___
The mass is not moving through some distance, so the product of force and distance is zero.
Explanation:
Given that,
She walks in east,
Speed = 0.80 m/s
Time = 4.0 min
In north,
Speed = 0.50 m/s
Time = 5.5 min
In west,
Speed = 1.1 m/s
Time = 2.8 min
(a). We need to calculate the unit-vector velocities for each of the legs of her journey.
The velocity of her in east
(b). We need to calculate the unit-vector displacements for each of the legs of her journey
Using formula of displacement
In east ,
In north,
In west,
(c). We need to calculate the net displacement from the postal truck after her journey is complete
Put the value in the formula
We need to calculate the magnitude of the displacement
The magnitude of the displacement is 165.16 m.
Hence, This is the required solution.
