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Verizon [17]
3 years ago
7

The planet whose distance from the sun equals 1 a.u. is: venus earth mars jupiter

Physics
2 answers:
son4ous [18]3 years ago
7 0
The answer is Earth. hope this helped

Katarina [22]3 years ago
7 0

earth is the correct answer

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What is the function of mitocondria? Pls Anyone
Anastasy [175]

Explanation:

Mitochondria is called the 'power house' because It is the site for respiration. It is also responsible for conversation of food to usable energy.

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3 years ago
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Write the answer in scientific notation, using the wanted unit.
lora16 [44]

Answer:

1.51 x 10^4 kg

Explanation:

(1.26 x 10^4 kg) + (2.5 x 10^6 g)

= 12600 kg + 2500000 g

= 12600 kg + (2500000 g / 1000 )

= 12600 kg + 2500 kg

= 15100 kg

= 1.51 x 10^4 kg

8 0
3 years ago
I need help in Physiology!!!!!!
Alisiya [41]

Perception is the sensory experience of the world. It involves both recognizing environmental stimuli and actions in response to these stimuli. Through the perceptual process, we gain information about the properties and elements of the environment that are critical to our survival.

5 0
2 years ago
For the electric circuit given below, calculate: 3 (i) the equivalent resistance of the circuit, (ii) the total current drawn fr
Daniel [21]

Answer:

1)31/3Ω

2)18/31A

3)4.06V

Explanation:

According to the diagram and 10 Ω resistors are parallel to each other, parallel resistor can be calculated using the formula below

1/R= 1/R1 + 1/R2

But we know R1= 5 Ω and R2= 10 Ω

1/R= 1/5 + 1/10

R= 10/3 Ω

=3.33 Ω

Then if we follow the given figure, 10/3 Ω and 7Ω are now in series then

Req = 10/3 +7

Req= 31/3 Ω

Therefore, equivalent resistance = 31/3 Ω

According to ohms law we know that V= IR

Then I= V/R

Where I= current

R= resistance

V= voltage

I= 6/(31/3)

I= 18/31A

We can now calculate the voltage accross the resistor which is

V=(18/31)× 7

V=4.06V

Therefore, the voltage accross the 7 ohm resistor is 4.06V

CHECK THE FIQURE AT THE ATTACHMENT

3 0
3 years ago
A spring has a force constant of 310.0 N/m. (a) Determine the potential energy stored in the spring when the spring is stretched
skad [1K]

Answer:

(a) 0.2618 J

(b)  0.1558 J

(c) 0 J

Explanation:

from Hook's Law,

The energy stored in a stretched spring = 1/2ke²

Ep = 1/2ke² ......................... Equation 1

Where k = spring constant, e = extension, E p = potential energy stored in the spring.

(a) When The spring is stretched to 4.11 cm,

Given: k = 310 N/m, e = 4.11 cm = 0.0411 m

Substituting these values into equation 1

Ep = 1/2(310)(0.0411)²

Ep = 155(0.0016892)

Ep =155×0.0016892

Ep = 0.2618 J.

(b) When the spring is stretched 3.17 cm

e = 3.17 cm = 0.0317 m.

Ep = 1/2(310)(0.0317)²

Ep = 155(0.0317)²

Ep = 155(0.0010049)

Ep = 0.155758 J

Ep ≈ 0.1558 J.

(c) When the spring is unstretched,

e = 0 m, k = 310 N/m

Ep = 1/2(310)(0)²

Ep = 0 J.

6 0
3 years ago
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