Check all of the statements that are true.
1 answer:
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<h2>Hey There!</h2><h2>_____________________________________</h2><h2>Answer:</h2><h2>_____________________________________</h2>
ATOMIC NUMBER: It is the number of protons present in the nucleus of every atom
MASS NUMBER: It is the number of nucleon. Nucleon are the number of proton and neutrons present in the nucleus.
PROTON NUMBER: Proton number equal to the atomic number.
ELECTRON NUMBER: Electron Number is equal to the atomic number.
NEUTRON NUMBER: It is Mass Number - Atomic Number.
CHARGE: It is due to the addition or removal of the electron. + charge when electron removed and - charge when electron is added.
SYMBOL: It is represented as,
Z is Mass Number
A is Atomic Number
<h2>_____________________________________</h2><h2>Worksheet:</h2>(I) ATOMIC NUMBER: 17
MASS NUMBER: 35.5
PROTON NUMBER: 17
ELECTRON NUMBER: 17
NEUTRON NUMBER: 18.5
CHARGE: 0
<h2>_____________________________________</h2>(II) ATOMIC NUMBER: 71
MASS NUMBER: 180
PROTON NUMBER: 71
ELECTRON NUMBER: 71
NEUTRON NUMBER: 109
CHARGE: 0
<h2>_____________________________________</h2>(III) ATOMIC NUMBER: 40
MASS NUMBER: 86
PROTON NUMBER: 40
ELECTRON NUMBER: 38
NEUTRON NUMBER: 46
CHARGE: +2
<h2>_____________________________________</h2>(IV) ATOMIC NUMBER: 92
MASS NUMBER: 238
PROTON NUMBER: 92
ELECTRON NUMBER: 86
NEUTRON NUMBER: 146
CHARGE: +6
<h2>_____________________________________</h2>(V) ATOMIC NUMBER: 82
MASS NUMBER: 206
PROTON NUMBER: 82
ELECTRON NUMBER: 78
NEUTRON NUMBER: 124
CHARGE: +4
<h2>_____________________________________</h2>(VI) ATOMIC NUMBER: 34
MASS NUMBER: 79
PROTON NUMBER: 34
ELECTRON NUMBER: 36
NEUTRON NUMBER: 45
CHARGE: -2
<h2>_____________________________________</h2>(VII) ATOMIC NUMBER: 48
MASS NUMBER: 113
PROTON NUMBER: 48
ELECTRON NUMBER: 49
NEUTRON NUMBER: 65
CHARGE: -1
<h2>_____________________________________</h2>(VIII) ATOMIC NUMBER: 21
MASS NUMBER: 42
PROTON NUMBER: 21
ELECTRON NUMBER: 21
NEUTRON NUMBER: 21
CHARGE: 0
<h2>_____________________________________</h2>(IX) ATOMIC NUMBER:
MASS NUMBER:
PROTON NUMBER:
ELECTRON NUMBER:
NEUTRON NUMBER:
CHARGE:
<h2>_____________________________________</h2>(X) ATOMIC NUMBER: 83
MASS NUMBER: 209
PROTON NUMBER: 83
ELECTRON NUMBER: 80
NEUTRON NUMBER: 126
CHARGE: +3
<h2>_____________________________________</h2>(XI) ATOMIC NUMBER: 47
MASS NUMBER: 108
PROTON NUMBER: 47
ELECTRON NUMBER: 47
NEUTRON NUMBER: 61
CHARGE: 0
<h2>_____________________________________</h2>(XII) ATOMIC NUMBER: 49
MASS NUMBER: 116
PROTON NUMBER: 49
ELECTRON NUMBER: 46
NEUTRON NUMBER: 67
CHARGE: +3
<h2>_____________________________________</h2>(XIII) ATOMIC NUMBER: 53
MASS NUMBER: 128
PROTON NUMBER: 53
ELECTRON NUMBER: 54
NEUTRON NUMBER: 75
CHARGE: -1
<h2>_____________________________________</h2>(XIV) ATOMIC NUMBER: 76
MASS NUMBER: 188
PROTON NUMBER: 76
ELECTRON NUMBER: 72
NEUTRON NUMBER: 112
CHARGE: +4
<h2>_____________________________________</h2><h2>Best Regards,</h2><h2>'Borz'</h2><h2 />Aromatic compounds are compounds that contain carbon-carbon multiple bonds.
The question did not mention that a heteroatom is present in the compound so we can assume that there is none of such. In that case, the compound contains only hydrogen and carbon.
So,
(CH)n = 78
where n is the number of each atom present.
(12 +1)n = 78
n = 78/13
n = 6
The molecular formula of the compound is C6H6
When C6H6 is treated with .conc.HNO3/conc.H2SO4 the compound shown in image 1 is formed. The reaction occurs at the C-C multiple bond.
When C6H6 is reacted with chlorine in the presence of sunlight, hexachlorobenzene (shown in image 2 attached) is formed.
