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torisob [31]
3 years ago
8

When an atom of uranium-235 is bombarded with neutrons, it splits into smaller nuclei and produces a great amount of energy. thi

s nuclear process is called fission. fusion. decomposition. chain reaction. ionization?
Chemistry
2 answers:
Scorpion4ik [409]3 years ago
8 0

<u>Answer:</u> The nuclear process for the splitting of U-235 nuclei is nuclear fission process.

<u>Explanation:</u>

Nuclear fission reactions are defined as the reaction in which, the heavier atoms splits into two or more lighter atoms. The number of atoms formed in this reaction increases from the given atoms.

Nuclear fusion reactions are defined as the reaction in which, two or more lighter atoms combine to form a heavier atom. The number of atoms formed in this reaction decreases from the given atoms.

Decomposition reaction is defined as the reaction in which a single large substance breaks down into two or more smaller substances.

Chain reactions are defined as the reaction in which the neutrons that are released in the previous fission reaction act as the starting material in the next reaction. Thus, this process continues to many reactions.

Ionization reaction is defined as the reaction in which an ionic compound dissociates into its ions when dissolved in aqueous solution.

The reaction for the fission of U-235 in smaller nuclei follows:

^{235}_{92}\textrm{U}\rightarrow ^{90}_{38}\textrm{Sr}+^{144}_{54}\textrm{Xe}+2^1_0\textrm{n}

Hence, the nuclear process for the splitting of U-235 nuclei is nuclear fission process.

lilavasa [31]3 years ago
3 0
It's nuclear fission: the splitting of the nucleus
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What is the name of the society that scientist form to bring about use one universal system of measurements? (Please hurry)
Katarina [22]

The International Bureau of Weights and Measures is the society that scientist form to bring about one universal system of measurements.

<u>Explanation:</u>

Every theoretical assumptions should be proved experimentally and for that we need a specific system to measure or quantify parameters used in those experiments or the outcome results variables.

The measurements of length should be done by measuring them in meters only and not by liters. The physical properties of every materials should have a particular way of measuring them and this is decided by the International Bureau of Weights and Measures.

They also decide the units of each measurements and the standardization of each units and weights are also done by this society.

6 0
3 years ago
Which of the following is the best definition of radiation?
mafiozo [28]

Answer: Option (D) is the correct answer.

Explanation:

When heat or energy is transferred through the space in the form of waves or through a material medium then it is know as radiation.

For example, when we take Sun bath then our body gets warm due to solar radiation.

For transfer of heat through radiation it is not necessary that the objects have to in contact with each other.

Thus, we can conclude that out of the given options, the transmission of heat without any contact.

6 0
4 years ago
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eimsori [14]

Answer:

b

Explanation:

8 0
3 years ago
If you have access to stock solutions of 1.00 M H3PO4, 1.00 M of HCl, and 1.00 M NaOH solution, (and distilled water of course),
garri49 [273]

Answer:

0.10L of 1.00M of H₃PO₄ and 0.1613L of 1.00M NaOH

Explanation:

The pKa's of phosphoric acid are:

H₃PO₄/H₂PO₄⁻ = 2.1

H₂PO₄⁻/HPO₄²⁻ = 7.2

HPO₄²⁻/PO₄³⁻ = 12.0

To make a buffer with pH 9.40 we need to convert all H₃PO₄ to H₂PO₄⁻ and an amount of H₂PO₄⁻ to HPO₄²⁻

To have a 50mM solution of phosphoures we need:

2L * (0.050mol / L) = 0.10 moles of H₃PO₄

0.10 mol * (1L / mol) = 0.10L of 1.00M of H3PO4

To convert the H₃PO₄ to H₂PO₄⁻ and to HPO₄²⁻ must be added NaOH, thus:

H₃PO₄ + NaOH → H₂PO₄⁻ + H₂O + Na⁺

H₂PO₄⁻ + NaOH → HPO₄²⁻ + H₂O + Na⁺

Using H-H equation we can find the amount of NaOH added:

pH = pKa + log [A⁻] / [HA] <em>(1)</em>

<em>Where [A-] is conjugate base, HPO₄²⁻ and [HA] is weak acid, H₂PO₄⁻</em>

<em>pH = 7.40</em>

<em>pKa = 7.20</em>

[A-] + [HA] = 0.10moles <em>(2)</em>

Replacing (2) in (1):

7.40 = 7.20 + log 0.10mol - [HA] / [HA]

0.2 = log 0.10mol - [HA] / [HA]

1.5849 = 0.10mol - [HA] / [HA]

1.5849 [HA] = 0.10mol - [HA]

2.5849[HA] = 0.10mol

[HA] = 0.0387 moles = H₂PO₄⁻ moles

That means moles of HPO₄²⁻ are 0.10mol - 0.0387moles = 0.0613 moles

The moles of NaOH needed to convert all H₃PO₄ in H₂PO₄⁻ are 0.10 moles

And moles needed to obtain 0.0613 moles of HPO₄²⁻ are 0.0613 moles

Total moles of NaOH are 0.1613moles * (1L / 1mol) = 0.1613L of 1.00M NaOH

Then, you need to dilute both solutions to 2.00L with distilled water.

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