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2 years ago

How are the functions of the mouth and stomach similar to each other

Chemistry

1 answer:

never [62]2 years ago

7 0

Answer:

they both break down food

Explanation:

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What reaction will take place if h2o is added to a mixture of nanh2/nh3? draw the products of the reaction (without sodium ion)?

Maru [420]

When sodium amide i.e. $NaNH_{2}$ reacts with water i.e. $H_{2}O$ results in the formation of sodium hydroxide i.e. $NaOH$ and ammonia $NH_{3}$ .

The chemical reaction is given by:

$NaNH_{2}+H_{2}O\rightarrow NH_{3}+NaOH$

Now, when ammonia i.e. $NH_{3}$ reacts with water results in the formation of ammonium hydroxide i.e. $NH_{4}OH$

The chemical reaction is given by:

$NH_{3}+H_{2}O\rightarrow NH_4OH$

Thus, the products of the above reactions are ammonia and ammonium hydroxide (without sodium ion).

The structures of the products are shown in figure (1): ammonium hydroxide and figure (2) ammonia.

8 0

3 years ago

When a 1.00 L sample of water from the surface of the Dead Sea (which is more than 400 meters below sea level and much saltier t

Harlamova29_29 [7]

Answer: Molarity of $MgCl_2$ in the original sample was 1.96M

Explanation:

Molarity is defined as the number of moles of solute dissolved per liter of the solution.

$Molarity=\frac{\text{no of moles}}{\text{Volume in L}}$

${\text {moles of solute}=\frac{\text {given mass}}{\text {molar mass}}=\frac{186g}{95g/mol}=1.96$

Now put all the given values in the formula of molarity, we get

$Molarity=\frac{1.96}{1.00L}$

$Molarity=1.96mol/L$

Thus molarity of $MgCl_2$ in the original sample was 1.96M

4 0

3 years ago

How many grams of material is lost in the aqueous phase if two extractions are carried out on 100 mL of a 5% (m/v) aqueous solut

san4es73 [151]

Answer:

4.94g of material

Explanation:

Partition coefficient (Kp) of a substance is defined as the ratio between concentration of organic solution and aqueous solution, that is:

Kp = 8 = Concentration in Ethyl acetate / Concentration in water

100mL of a 5% solution contains 5g of material in 100mL of water. Thus:

8 = X / 100mL / (5g-X) / 100mL

Where X is the amount of material in grams that comes to the organic phase.

8 = X / 100mL / (5g-X) / 100mL

8 = 100X / (500-100X)

4000 - 800X = 100X

4000 = 900X

4.44g = X

Thus, in the first extraction you will lost 4.44g of material from the aqueous phase.

And will remain 5g-4.44g = 0.56g.

In the second extraction:

8 = X / 100mL / (0.56g-X) / 100mL

8 = 100X / (56-100X)

448 - 800X = 100X

448 = 900X

0.50g = X

In the second extraction, you will extract 0.50g of material

Thus, after the two extraction you will lost:

4.44g + 0.50g = 4.94g of material

6 0

2 years ago

Out of the 3 of these

Delvig [45]

Electrons can be transformed from on object to another , (can you mark me brainlyest)

6 0

2 years ago

What is this thermodynamic?

VLD [36.1K]

Answer:

oh coooool

I have one Id it is on ace with maybe 5800 points

maybe this picture will help in something

6 0

2 years ago