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diamong [38]
2 years ago
13

How are the functions of the mouth and stomach similar to each other

Chemistry
1 answer:
never [62]2 years ago
7 0

Answer:

they both break down food

Explanation:

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Use Table 1: Analysis of Decay in the laboratory guide to answer this question: Scientists find a piece of wood that is thought
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<span>We are given the initial amount of 1 million carbon-14 atoms and the final amount which is 1/16 of the current atmospheric 14C levels. Also, the half life of carbon is </span>5,750 years. WE can use the decay formula

Aₓ = A₀e^-(ln2/t1/2)t
1,000,000(1/16) = (1,000,000)e^-(ln2/5750)t
t = 23,000 years
6 0
2 years ago
1. Though Florida receives a lot of rainfall, only 1 percent remains available for people to use or drink. What happens to the r
timama [110]
<span>I am sure these answers are correct cause I've checked all of them. Here they are : 

1) The thing which might h</span>appen to the rest of the water is that 61% of that water leaves the ground through evapotranspiration and <span>38% will flow into the Atlantic Ocean. 
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8 0
3 years ago
Compare and contrast alpha beta and gamma radiation
Evgen [1.6K]
There are usually 3 topics used to compare types of radiation: 

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Penetrative power 
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Range in air
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8 0
2 years ago
How many moles of magnesium are in 35g of magnesium?
maksim [4K]
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3 0
2 years ago
A lead mass is heated and placed in a foam cup calorimeter containing 40.0 mL of water at 17.0°C. The water reaches a temperatur
lbvjy [14]

Answer: 502 Joules

Explanation:

To calculate the mass of water, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Density of water = 1 g/mL

Volume of water = 40.0 mL

Putting values in above equation, we get:

1g/mL=\frac{\text{Mass of water}}{40.0mL}\\\\\text{Mass of water}=(1g/mL\times 40.0mL)=40.0g

When metal is dipped in water, the amount of heat released by lead will be equal to the amount of heat absorbed by water.

Heat_{\text{absorbed}}=Heat_{\text{released}}

The equation used to calculate heat released or absorbed follows:

q=m\times c\times \Delta T

q = heat absorbed by water

m = mass of water = 40.0 g

T_{final} = final temperature of water = 20.0°C

T_{initial = initial temperature of water = 17.0°C

c = specific heat of water= 4.186 J/g°C

Putting values in equation 1, we get:

q=40.0\times 4.186\times (20.0-17.0)]

q=502J

Hence, the joules of heat were re-leased by the lead is 502

5 0
3 years ago
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